Float to int in haskell

Question

In this Haskell code:

power a r = [a*(truncate (r**i)) | i <- e]
    where e = [0,10]

I am getting an error with the ** operation because I believe it makes a float. Is there a way to convert it to an int?

Gabriella Gonzalez · Accepted Answer · 2013-03-10 02:40:06Z

4

I don't know what you mean by getting an error since your code type-checks, but you probably want the ^ operator:

(^) :: (Integral b, Num a) => a -> b -> a

Your code type-checks just fine with that, too:

power a r = [a*(r^i) | i <- e]
    where e = [0,10]

answered Mar 10, 2013 at 2:40

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