C# XML serializing with attributes for every element

Question

I want to create the following xml:

 <StartLot>
      <fileCreationDate level="7">201301132210</fileCreationDate>
      <fmtVersion level="7">3.0</fmtVersion>
 </StartLot>

Below is the Serialization code:

[Serializable]
class StartLot
{
    public fileCreationDate{get; set;}

    [XmlAttribute("level")] 
    public string level = "7";

    public fmtVersion{get; set;}

    [XmlAttribute("level")] 
    public string level = "7"; ??
}

Since I already declared attribute level, how do I add the last attribute?

Yu may have to create another type, take a look at this answer stackoverflow.com/a/4154801/525138 — Dutts
– Dutts, Commented Mar 15, 2013 at 20:24
The [Serializable] attribute does not affect XML serialization, but it shouldn't break anything leaving it in. — Kenneth K.
– Kenneth K., Commented Mar 15, 2013 at 20:32

carlosfigueira · Accepted Answer · 2013-03-15 20:25:29Z

You can use a wrapped class to store both values, as in the example below:

public class StackOverflow_15441384
{
    const string XML = @"<StartLot>
                               <fileCreationDate level=""7"">201301132210</fileCreationDate>
                               <fmtVersion level=""7"">3.0</fmtVersion>
                            </StartLot>";
    public class StartLot
    {
        [XmlElement("fileCreationDate")]
        public LevelAndValue FileCreationDate { get; set; }
        [XmlElement("fmtVersion")]
        public LevelAndValue FmtVersion { get; set; }
    }
    public class LevelAndValue
    {
        [XmlAttribute("level")]
        public string Level { get; set; }
        [XmlText]
        public string Value { get; set; }
    }
    public static void Test()
    {
        XmlSerializer xs = new XmlSerializer(typeof(StartLot));
        StartLot sl = (StartLot)xs.Deserialize(new MemoryStream(Encoding.UTF8.GetBytes(XML)));
        Console.WriteLine("FCD.L = {0}", sl.FileCreationDate.Level);
        Console.WriteLine("FCD.V = {0}", sl.FileCreationDate.Value);
        Console.WriteLine("FV.L = {0}", sl.FmtVersion.Level);
        Console.WriteLine("FV.V = {0}", sl.FmtVersion.Value);
    }
}

I4V · Accepted Answer · 2013-03-15 20:26:18Z

0

I always find Linq To Xml easier to use

var xDoc = XDocument.Parse(xml); /* XDocument.Load(filename); */

var items = xDoc.Root.Descendants()
                .Select(e => new
                {
                    Name = e.Name.LocalName,
                    Level = e.Attribute("level").Value,
                    Value = e.Value
                })
                .ToList();

answered Mar 15, 2013 at 20:26

I4V

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1 Comment

code4life Over a year ago

I'm just curious to know why you would replace a POCO-based serialization with manual XML generation/parsing (albeit via Xlinq)? Plus, your approach basically guts out any possibility of checking vs a schema.

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