PHP nested loop echos must not break into new line

Question

Here is my code segment:

for($i=0;$i<23;$i++){
    echo "<div id=slotshead></div>";
    for($j=0;$j<30;$j++) {
        echo " <div id=slots></div>";
    }
    echo '<br>';
}

But, it doesn't work. I want the two echo statements inside the loop to be continued, not break into a new line. How can I fix it?

If you dont want it to create new lines why do you have echo '<br>'? — user1120369
– user1120369, Commented Mar 16, 2013 at 2:03
Why are you applying the CSS to the H3 when that's what's wrapping all the block-level content within it? Further, you're explicitly putting a line-break after each $i loop... I'm completely lost on what you're trying to do. — animuson
– animuson ♦, Commented Mar 16, 2013 at 2:03
I want the two echos inside the loops to be joined as one line.... — mohzameer
– mohzameer, Commented Mar 16, 2013 at 2:04

hjpotter92 · Accepted Answer · 2013-03-16 02:15:26Z

1

If you just want to have each looped output display in a single line, you were nearly there.

Add the following to CSS; and you're done.

h3 > div {
    display: inline-block;
}

It'll generate the output as this fiddle.

answered Mar 16, 2013 at 2:15

hjpotter92

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Comments

Aiias · Accepted Answer · 2013-03-16 02:11:29Z

0

If I understand what you're asking... this will combine your loops:

 for ($i = 0; $i < 23; $i++) {
   echo "<div id=slotshead></div>";
   for ($j = 0; $j < 30; $j++) {
     echo " <div id=slots></div>";
   }
 }
 echo '<br>';

answered Mar 16, 2013 at 2:11

Aiias

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2 Comments

mohzameer Over a year ago

I need slothead to be at first. e.g [slothead][slot][slot][slot][slot]<br> [slothead][slot][slot][slot][slot]

Aiias Over a year ago

Edited and moved the <br /> outside of the loops. What kind of output are you expecting? (Where should the <br />s be?)

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