32 bit hex string to floating point number in java

Question

I have the following string "0x4B196DAF". I want to get output like "10055087.000000".

My piece of code is showing a strange output like "1.0055087E7"

long l = Long.parseLong(hexval, 16);
return Float.intBitsToFloat(l.intValue());

I have also tried with

long l = Long.parseLong(hexval, 16);
return Double.longBitsToDouble(l.longValue());

But nothing helpful. I have check few website which showing the correct output. I can't find out the problem exactly.

maybe look at docs.oracle.com/javase/1.5.0/docs/api/java/math/BigDecimal.html — SpaceCowboy
– SpaceCowboy, Commented Mar 17, 2013 at 18:39
1.0055087E7 is simply 10055087.000000 in another notation. You want to look into java's formatting options for printing numbers. docs.oracle.com/javase/7/docs/api/java/util/Formatter.html might be useful. — user406009
– user406009, Commented Mar 17, 2013 at 18:41

Laura Konda · Accepted Answer · 2013-03-17 19:40:33Z

3

I assume you want to print it out as a string, call somewhere toString(). It will give a scientific notation after limit is met.

You can try to use:

int hex = 0x4B196DAF;
float f = Float.intBitsToFloat(hex);
System.out.println(f);
System.out.printf("%f", f);

Output ....

1.0055087E7
10055087.00000010055087

or if you want you can try using NumberFormat, which will allow you to set a minimum fraction digits:

NumberFormat nf = NumberFormat.getInstance();
nf.setGroupingUsed(false);
nf.setMinimumFractionDigits(6);

System.out.println(nf.format(f));

output ....

10055087.000000

I hope it will help.

answered Mar 17, 2013 at 19:40

Laura Konda

1062 bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1