Couldn't Access Array inside If statement which is present in the for loop in Javascript

Question

JAVASCRIPT:

function identifybrand ( allproducts,favBrand){ 
  var favBrandList = new Array();
  var prodType = document.getElementById('prodType').value;
  for (var i=0;i<=allproducts.length;i++) {
    if (favBrand == allproducts[i].brandName) {
      favBrandList.push(allproducts[i]);
    }
  }
  alert(favBrandList);
}

I couldnt access the favBrandList array outside the for loop. Does anyone have any idea why i m not able to access it?

Are you getting any values in allproducts? Have you tried alerting the values? — Aashray
– Aashray, Commented Mar 26, 2013 at 10:19
yeah....if i put alert inside for loop i can see the array. but its couldn't access it outside. — Abhimanyu
– Abhimanyu, Commented Mar 26, 2013 at 10:35

Arun P Johny · Accepted Answer · 2013-03-26 10:19:50Z

1

The reason should be you are getting a script error in the loop.

Your loop is faulty, i<=allproducts.length is wrong it should be i<allproducts.length.

Array index starts from 0 to length - 1, so when i equals allproducts.length, allproducts[i] becomes undefined and allproducts[i].brandName will throw a script error.

function identifybrand(allproducts, favBrand) {
    var favBrandList = new Array();
    var prodType = document.getElementById('prodType').value;
    for (var i = 0; i < allproducts.length; i++) {
        if (favBrand == allproducts[i].brandName) {
            favBrandList.push(allproducts[i]);
        }
    }
    alert(favBrandList);
}

answered Mar 26, 2013 at 10:19

Arun P Johny

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4 Comments

Abhimanyu Over a year ago

Thanks for your response. But still i m not able to access it.

Arun P Johny Over a year ago

what do you mean by not able to access?

Abhimanyu Over a year ago

i mean if i put the alert inside the for loop, i can actually see the array forming. But if i try put alert for favBrandList array out side the for loop, i m not getting any alert.

Abhimanyu Over a year ago

Thanks for your help. Right from the beginning i was putting i<=. :-)

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