Javascript - define function with variable

Question

Let's say I have the following code

var $variable = $('<li/>', { 
    tabindex: 0,
    click: function() {
        //more code in here
    }
}

is it possible to define the click: with a variable? Baring in mind it is already inside a variable and will also include an if statement, like so:

if(condition) {
    var functiontype = 'click';
}
else {
    var functiontype = 'hover';
}
var $variable = $('<li/>', { 
    tabindex: 0,
    functiontype: function() {
        //more code in here
    }
}

I tried doing this but it didn't work. Can someone please point me in the right direction?

Carlos · Accepted Answer · 2013-03-31 16:16:56Z

2

if(condition) {
    var functiontype = 'click';
}
else {
    var functiontype = 'hover';
}

var options = {};
options["tabindex"] = 0;
options[functiontype] = function(){
    // your code
}
var $variable = $('<li/>', options);

answered Mar 31, 2013 at 16:16

Carlos

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Comments

Denys Séguret · Accepted Answer · 2013-03-31 16:00:34Z

0

You may do the reverse :

var $variable = $('<li/>', { 
    tabindex: 0
};
$variable[condition?'click':'hover'] = function(){
   // the code here
}

answered Mar 31, 2013 at 16:00

Denys Séguret

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