Django Admin: Getting request in ModelForm's constructor

Question

The below code removes certain values from a drop down menu. It works fine but I want to remove the value if the user lacks certain permissions. How can I access request.user in the ModelForm's constructor? Or is there a better way to accomplish what I am trying to do?

class AnnouncementModelForm(forms.ModelForm):

    def __init__(self, *args, **kwargs):
        super(AnnouncementModelForm, self).__init__(*args, **kwargs)
        self.fields["category"].queryset = AnnouncementCategory.objects.filter(can_post=True)

lprsd · Accepted Answer · 2009-10-16 10:56:01Z

1

How can I access request.user in the ModelForm's constructor?

To use it in the Form constructor, just pass the request to it.

class AnnouncementModelForm(forms.ModelForm):

    def __init__(self, request, *args, **kwargs):
        super(AnnouncementModelForm, self).__init__(*args, **kwargs)
        qs = request.user.foreignkeytable__set.all()
        self.fields["category"].queryset = qs

answered Oct 16, 2009 at 10:56

lprsd

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2 Comments

orwellian Over a year ago

Thanks for your reply. Are you sure about that though? Because I am getting this TypeError: __init__() takes at least 2 non-keyword arguments (1 given)

lprsd Over a year ago

Pass the "request" argument into the Class creation! How else does it get it? AnnouncementModelForm(request)

orwellian · Accepted Answer · 2009-10-16 11:24:52Z

1

Ok here is how I solved it:

def formfield_for_foreignkey(self, db_field, request, **kwargs):
    if db_field.name == "category" and not request.user.has_perm('can_post_to_all'):
        kwargs["queryset"] = AnnouncementCategory.objects.filter(can_post=True)
        return db_field.formfield(**kwargs)
    return super(AnnouncementAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)

answered Oct 16, 2009 at 11:24

orwellian

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