php numeric array select values greater than a number and lower than another and save it to a new array

Question

I have one array(dynamically created) that contains the following numbers

$numbers = array (200, 400, 600, 800, 1000, 1200, 1400, 1600, 1800, 2000, 3000, 4000, 5000, 6000, 7000, 8000, 9000, 10000, 12000, 14000, 15000, 16000, 18000, 20000, 21000, 24000, 25000, 27000, 30000, 35000, 40000, 45000, 50000, 60000, 70000, 75000, 80000, 90000, 100000, 105000, 120000, 135000, 140000, 150000, 160000, 180000, 200000, 250000, 300000, 350000, 400000, 450000, 500000, 600000, 700000, 800000, 900000, 1000000)

I want to create new array (filtered) by >= and <= for example the new array to contains numbers greater or equal(>=) than 800 and lower or equal(<=) than 1600

New Array
(
    [0] => 800
    [1] => 1000
    [2] => 1200
    [3] => 1400
    [4] => 1600
)

is that possible without using foreach?

^ array_filter($numbers, function($n){ return $n >= 800 && $n <= 1600 } — elclanrs
– elclanrs, Commented Apr 2, 2013 at 23:14
yes! I did not know it how to pass two variables to array_filter. thanks both of you! — AkisC
– AkisC, Commented Apr 2, 2013 at 23:17

Mark Baker · Accepted Answer · 2013-04-02 23:16:48Z

29

$min = 800;
$max = 1200;
$newNumbers = array_filter(
    $numbers,
    function ($value) use($min,$max) {
        return ($value >= $min && $value <= $max);
    }
);

answered Apr 2, 2013 at 23:16

Mark Baker

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3 Comments

Mark Baker Over a year ago

@CJDennis - the significant difference is that "use" variable values ($min and $max) are fixed (and so must exist) at the point where the anonymous/lambda function is defined, whereas normal arguments (in this case $value) are passed when the function is called.... it doesn't make much difference in this case, but may in other cases

Mark Baker Over a year ago

The other difference is that the callback for array_filter() accepts only a specific argument or argument set (you can pass the key as well in recent versions of PHP), so you need to use use in that case to pass additional arguments to the function

CJ Dennis Over a year ago

I've been wondering how to pass extra variables to lambda functions and now I know!

Arnav Borborah · Accepted Answer · 2018-01-17 12:31:45Z

12

You are looking for array_filter http://php.net/manual/en/function.array-filter.php

A good example of use would be:

array_filter($numbers, function($n){ 
    return $n >= 800 && $n <= 1600;
});

edited Jan 17, 2018 at 12:31

Arnav Borborah

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answered Apr 2, 2013 at 23:18

Unseen Revolution

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