Passing multiple parameters to a function through an Eval

Question

I am tyring to pass two values to a function through an Eval.

My function:

public static string ValidateSalary(int salaryFrom, int salaryTo)
{
    string salary = string.Empty;

    if (salaryFrom == salaryTo)
    {
        salary = "£" + salaryFrom.ToString();
    }
    else 
    {
        salary = "£" + salaryFrom.ToString() + " - £" + salaryTo.ToString();
    }
    return salary;
}

My Eval attempt:

<%# ValidateSalary(Eval("SalaryFrom", "SalaryTo")) %>

My error:

Error   5   No overload for method 'ValidateSalary' takes 1 arguments

I've tried multiple ways of formatting it and I can't figure it out!

<%# ValidateSalary(Eval("SalaryFrom"), Eval("SalaryTo")) %> — Julián Urbano
– Julián Urbano, Commented Apr 7, 2013 at 15:44
@lauw0203 If you see my answer stackoverflow.com/a/15864175/159270 on your previous question, you can notice that you can get any parametre on code behind, just by passing the DataItem — Aristos
– Aristos, Commented Apr 7, 2013 at 16:07

Community · Accepted Answer · 2017-05-23 12:15:21Z

1

By sending the DataItem on code behind, you can get any parameter as:

<%#RenderSalaryType(Container.DataItem)%>

and on code behind

protected string RenderSalaryType(object oItem)
{
    int salaryType = (int)DataBinder.Eval(oItem, "SalaryType");
    string salaryFrom = (int)DataBinder.Eval(oItem, "SalaryFrom").ToString();
    string salaryTo = (int)DataBinder.Eval(oItem, "SalaryTo").ToString();

    // rest of your code
}

Similar to https://stackoverflow.com/a/15864175/159270

edited May 23, 2017 at 12:15

CommunityBot

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answered Apr 7, 2013 at 16:09

Aristos

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Comments

Amit Singh · Accepted Answer · 2013-04-07 15:45:16Z

0

You can Pass Like this...

<%# ValidateSalary(Convert.ToInt32(Eval("SalaryFrom")),Convert.ToInt32(Eval("SalaryTo"))) %>

answered Apr 7, 2013 at 15:45

Amit Singh

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1 Comment

wilcode Over a year ago

Thanks @amit-singh, I tried using convert on one but not the other, so I was still getting the error!

Adil · Accepted Answer · 2013-04-07 15:50:38Z

0

Use Eval twice

<%# ValidateSalary(Convert.ToInt32(Eval("SalaryFrom")), Convert.ToInt32(Eval("SalaryTo")) %>

edited Apr 7, 2013 at 15:50

answered Apr 7, 2013 at 15:44

Adil

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