MIPS Initializing array in a loop

Question

So I'm trying to put 10 numbers that are between 0-50 into an array.

    li  $t0, 0      #loopcounter = 0
    la  $a0, array
    addi    $a0, $0, 0  #initialize array index = 0
    loop:
            li  $v0, 5
            syscall
            blt $v0, 0, loop
            bgt $v0, 50, loop
            add $t0, $t0, 1   #increment loop counter

            sw  $a0, 0($a0)     # ERROR HERE #store value of $v0 at index 0
            addi    $a0, $a0, 4     # Increment the index by 4


            blt $t0, 10, loop

How would I go about putting those 10 numbers into my array at $a0 and then be able to access them later?

See the MIPS instruction set. Specifically the SW instruction. — Michael
– Michael, Commented Apr 8, 2013 at 12:17

Thanakron Tandavas · Accepted Answer · 2013-04-08 12:27:46Z

1

This will

addi $a0, $0, $0     # initialize index with 0
sw $v0, 0($a0)       # store value of $v0 at index 0
addi $a0, $a0, 4     # Increment the index by 4
sw $v0, 0($a0)       # store value of $v0 at index 1

and so on...

I left the loop part for you.

Why increment by 4 ?

Becuase integers in MIPS takes up 32 bits or 4 bytes

answered Apr 8, 2013 at 12:27

Thanakron Tandavas

5,7035 gold badges31 silver badges41 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

MIPS Initializing array in a loop

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related