PHP Echo out values of an array with ranges

Question

I am still learning PHP and have a bit of an odd item that I haven't been able to find an answer to as of yet. I have a multidimensional array of ranges and I need to echo out the values for only the first & third set of ranges but not the second. I'm having a hard time just finding a way to echo out the range values themselves. Here is my code so far:

$array = array(
    1=>range(1,4),
    2=>range(1,4),
    3=>range(1,4)
);

foreach(range(1,4) as $x)
{

    echo $x;
}

Now I know that my foreach loop doesn't even reference my $array so that is issue #1 but I can't seem to find a way to reference the $array in the loop and have it iterate through the values. Then I need to figure out how to just do sets 1 & 3 from the $array. Any help would be appreciated!

Thanks.

Hanky Panky · Accepted Answer · 2013-04-11 16:03:30Z

1

Since you don't want to show the range on 2nd index, You could try

<?php

$array = array(
    1=>range(1,4),
    2=>range(1,4),
    3=>range(1,4)
);

foreach($array as $i=>$range)
{
if($i!=2)
{
    foreach($range as $value)
    {
    echo $value;
    }
}
}

?>

Note: It's not really cool to name variables same as language objects. $array is not really an advisable name, but since you had it named that way, I didn't change it to avoid confusion

edited Apr 11, 2013 at 16:03

answered Apr 11, 2013 at 15:54

Hanky Panky

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Comments

Ivo Pereira · Accepted Answer · 2013-04-11 15:52:26Z

0

Do you want to do this?

foreach ($array as $item) {
    echo $item;
}

answered Apr 11, 2013 at 15:52

Ivo Pereira

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Nikolay Ivanov · Accepted Answer · 2013-04-11 15:52:44Z

0

You can use either print_r($array) or var_dump($array). The second one is better because it structures the output, but if the array is big - it will not show all of it content. In this case use the first one - it will "echo" the whole array but in one row and the result is not easy readable.

answered Apr 11, 2013 at 15:52

Nikolay Ivanov

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Martin Prikryl · Accepted Answer · 2013-04-11 15:56:59Z

0

Range is just an array of indexes, so it's up to you how to your want to represent it, you might want to print the first and the last index:

function print_range($range)
{
    echo $range[0] . " .. " . $range[count($range) - 1] . "\n";
}

To pick the first and the third range, reference them explicitly:

print_range($array[1]);
print_range($array[3]);

answered Apr 11, 2013 at 15:56

Martin Prikryl

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Comments

Charaf JRA · Accepted Answer · 2013-04-11 15:59:16Z

0

here is one solution:

$array = array(
1=>range(1,4),
2=>range(1,4),
3=>range(1,4)
);
   $i=0;

   foreach($array as $y)
   { $i++;
          echo "<br/>";

     if($i!=0){ foreach($y as $x)
       {
           echo $x;
       }
                      }
   }

edited Apr 11, 2013 at 15:59

answered Apr 11, 2013 at 15:52

Charaf JRA

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