This is my header file:
typedef int* Arg;
typedef int* Args[];
typedef int** ArgsList[];
typedef int (*ProcessStart)(Args);
typedef struct PCBEntry{
ProcessStart proc;
Args args;
int pid;
int curr_proc;
int sched_info;
int pc;
} PCBEntry;
I get the error on the Args argsline in the struct and I have no idea why.
Because you defined Args as int *[], the member args is effectively declared as
int *args[];
This is a flexible array member, and they are only allowed at the end of a structure.
If you meant to imply that Args was a pointer (in the same vein as char **argv), declare it as a pointer:
typedef int **Args;
Args from an array type to a pointer type. That might be a good solution, but it's a big change to the structure.Args isn't a VLA type. A VLA has a specified non-constant size; Args doesn't have a specified size at all.
Rather than using
typedef int* Args[];
and in your structure declaration
Args args;
you would be better served to just use the first type for your structure declaration...
Arg args[];
To be honest, I'm not even sure the the first one is a legal typedef, but it's only that I've never ever done anything like that with a typedef before. My gut tells me that it's not legal and therefore Args is undefined and thus the error you're getting. If I apply the right-left rule to that, then Args is a type that is an array of pointers to int... so, maybe it's legal, but it sure reads funny to my eye.
