How can I recursively replace a string with another in many files using bash?

Question

I need to write a script that replaces all the occurrences of a certain string to "replaceWithThisNewString" in all the files in a directory and all its sub directories. How can it be done?

Wrikken · Accepted Answer · 2013-04-14 20:04:18Z

3

find /path/to/dir -type f -exec sed -i 's/original/replacement/g' {} \+

Or if your find doesn't support \+:

find /path/to/dir -type f -exec sed -i 's/original/replacement/g' {} \;

answered Apr 14, 2013 at 20:04

Wrikken

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Kent · Accepted Answer · 2013-04-14 20:03:54Z

0

try this line:

find /aDir -type f |xargs sed -i 's/certainString/replaceWithThisNewString/g'

answered Apr 14, 2013 at 20:03

Kent

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1 Comment

Wrikken Over a year ago

Ḧm, if going the xargs route, I'd use find .... -print0 | xargs -0 ... just to be safe.

Gilles Quénot · Accepted Answer · 2013-04-14 20:46:20Z

0

Using bash4 :

shopt -s globstar # if not already enabled
sed -i '/certainString/s/certainString/replaceWithThisNewString/g' **

edited Apr 14, 2013 at 20:46

answered Apr 14, 2013 at 20:40

Gilles Quénot

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