Newton.JSON convert dynamic object to JObject instead of dynamic object

Question

string  result ="{"AppointmentID":463236,"Message":"Successfully Appointment Booked","Success":true,"MessageCode":200,"isError":false,"Exception":null,"ReturnedValue":null}"

   dynamic d = JsonConvert.DeserializeObject<dynamic>(result);

d.GetType () is Newtonsoft.Json.Linq.JObject

so how to deserialize it to dynamic object instead of JObject

Darin Dimitrov · Accepted Answer · 2013-04-19 15:30:13Z

4

It's not quite clear what is not working for you and why you care about the return type but you could directly access the properties of the deserialized object like this:

string result = @"{""AppointmentID"":463236,""Message"":""Successfully Appointment Booked"",""Success"":true,""MessageCode"":200,""isError"":false,""Exception"":null,""ReturnedValue"":null}";
dynamic d = JsonConvert.DeserializeObject<dynamic>(result);

string message = d.Message;
int code = d.MessageCode;
...

answered Apr 19, 2013 at 15:30

Darin Dimitrov

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7 Comments

sino Over a year ago

I cant access property directly because "d" is not dynamic object , but it is JObject so it will throw exception

Darin Dimitrov Over a year ago

"d" is not dynamic object: WRONG. d is a dynamic object because you declared it as dynamic and you can access any property you like. The JObject class has this nice property to automatically dispatch calls to its properties. Did you even try the code I have shown in my answer?

sino Over a year ago

that is the first impression when you didn't actually tried the code , try to execute that code and you will get error on string message = d.Message; because "Message" does not exists, and that is my issue

sino Over a year ago

you are right ,I executed the code outside of unit test and it worked, but inside unit test it converting it to JObject , that is weird

wilson0x4d Over a year ago

interesting, seems this happens whenever i deserialize a structured object which contains an array element, for example { "id": 1, "fail":["val1","val2"] }returns JObject and any late bound access results in a runtime binder exception

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Jakob Bowyer · Accepted Answer · 2013-04-19 15:30:12Z

1

You probably want something like

var values = JsonConvert.DeserializeObject<Dictionary<string, dynamic>>(json);

This might also suit your needs (untested)

dynamic d = JsonConvert.DeserializeObject<ExpandoObject>(json);

answered Apr 19, 2013 at 15:30

Jakob Bowyer

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