Regular expression for a string starting with some string

Question

I have some string, that has this type: (notice)Any_other_string (notes that : () has in this string`.

So, I want to separate this string to 2 part : (notice) and the rest. I do as follow :

private static final Pattern p1 = Pattern.compile("(^\\(notice\\))([a-z_A-Z1-9])+");
String content = "(notice)Stack Over_Flow 123";

        Matcher m = p1.matcher(content);

        System.out.println("Printing");

        if (m.find()) {
            System.out.println(m.group(0));
            System.out.println(m.group(1));
        }

I hope the result will be (notice) and Stack Over_Flow 123, but instead, the result is : (notice)Stack and (notice)

I cannot explain this result. Which regex is suitable for my purpose?

@user2264587 yes. I have add a space. but, group 3 just 3. not Stack Over_Flow 123 — hqt
– hqt, Commented Apr 20, 2013 at 11:45

ddmps · Accepted Answer · 2013-04-20 11:57:28Z

2

Issue 1: group(0) will always return the entire match - this is specified in the javadoc - and the actual capturing groups start from index 1. Simply replace it with the following:

System.out.println(m.group(1));
System.out.println(m.group(2));

Issue 2: You do not take spaces and other characters, such as underscores, into account (not even the digit 0). I suggest using the dot, ., for matching unknown characters. Or include \\s (whitespace) and _ into your regex. Either of the following regexes should work:

(^\\(notice\\))(.+)
(^\\(notice\\))([A-Za-z0-9_\\s]+)

Note that you need the + inside the capturing group, or it will only find the last character of the second part.

edited Apr 20, 2013 at 11:57

answered Apr 20, 2013 at 11:41

ddmps

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1 Comment

ddmps Over a year ago

@AntP Should've noticed that.. Goes to bed

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