How do I get jquery variable value to be read by PHP $_POST?

Question

I'm able to successfully get all the values from a multi-select form into one nice delimited variable, but I can't figure out how to get the value to my PHP script? How do I get the 'output' value read by PHP's $_POST array? Any help would. Be. Awesome. :D

<script type="text/javascript">
function ValidatePageForm() {
    var result = new Array();

    $("#select-to option").each(function() {
        result.push($(this).val());
    });

    var output = result.join("-");  
    alert(output);


}
</script>

Which value do you want go get where? I'm confused. Do you want get the value of $_POST "inserted" into jQuery or do you want to get the values from jQuery-function "inserted" into PHP? — bestprogrammerintheworld
– bestprogrammerintheworld, Commented Apr 24, 2013 at 5:15

xkeshav · Accepted Answer · 2013-04-24 04:36:59Z

1

suppose you have a form

<form>
<input type="hidden" name="output" id="output">
....
</form>

send javascript variable to HTML

var output = result.join("-");  
$('#output').val(output);

and when you submit the form you wil get data in $_POST['output']

answered Apr 24, 2013 at 4:36

xkeshav

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user1583267 Over a year ago

You're amazing. So simple. It works :). You saved me. Seriously this front-end stuff throws me for a loop. BUT give me crazy back-end work and I'll knock your socks off!

user2130360 · Accepted Answer · 2013-04-24 04:37:25Z

0

I believe your looking for something like echo $_POST['value']; ??

answered Apr 24, 2013 at 4:37

user2130360

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user1583267 Over a year ago

And yes I know about $_POST vars...but for some reason using this fancy jquery on the front-end with my multiselect - the variables are not being posted with the multiselect (it allows you to shift elements back and forth from one multiselect to another, then up/down to reorder - not your typical multiple select in plain HTML for my PHP to read...

deep2mail · Accepted Answer · 2013-04-24 04:48:50Z

0

You can use Jquery serialize to post all the data of the form including multi select

var submit_data = $('#output').serialize();
var post_data = submit_data ;
$.ajax({
    type: "POST",
    url: 'submitform.php',
    data: post_data,
    success: function(data)
    {
    }
});

You will get all the value in $_POST on submitform.php

Let me know it works for you

answered Apr 24, 2013 at 4:48

deep2mail

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