php array : in one line, how to get an unknown value from a known key?

Question

I have this array - it is a multidimensional array, and i don't know the 0 index :

Array
(
    [0] => Array
        (
            [foo] => 1111
            [bar] => example
        )

)

And I need, in one line, with native php functions, to get the value from the key bar. I tried much combination with current, key, array_keys, and so on. With current($array) I got :

Array
(
    [foo] => 1111
    [bar] => example
)

I discover array_keys, which allow me, with the second argument, to specify a value to find. But I didn't know the value, only the key, and array_values didnt propose a second argument to find (:o).

Here I am now : current(array_keys(array_flip(current($b))), 'bar') didn't work. But

$c = array_flip(current($b));
print_r(current(array_keys($c, 'bar')));

works - I get "example". (By the way, why these 2 lines are working and not the previous one ?).

And I know, it's ugly to use array_flip for this, but I don't know how to do otherwise. Any idea ? Thanks.

"The" key bar? Your array contains an "etc" part. Who says there's no other bar in there? Also, if you need to do it on one line, write a function. The function call would be an one-liner. — Jon
– Jon, Commented Apr 26, 2013 at 14:57
You are MASSSIVELY overthinking/overcomplicating things. Check out HankyPanky's answer below. — Marc B
– Marc B, Commented Apr 26, 2013 at 14:59
@Ash_ is it a multidimensional array ? I mean do you know the index 0 ? — HamZa
– HamZa, Commented Apr 26, 2013 at 15:03
@Ash_: Well, PHP 5.4 allows reset($array)['bar']. Is that what you want? — Jon
– Jon, Commented Apr 26, 2013 at 15:10

Hanky Panky · Accepted Answer · 2013-04-26 14:57:19Z

5

What stops you from using

$value=$myArray[0]["bar"];
echo $value;

answered Apr 26, 2013 at 14:57

Hanky Panky

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9 Comments

Niet the Dark Absol Over a year ago

But that's too simple and doesn't call functions! :p

Marc B Over a year ago

@jon: it is the answer, however. OP's obviously massively overcomplicating/overthinking things...

Hanky Panky Over a year ago

@Jon but isn't it what they are looking for?

Jon Over a year ago

@MarcB: How is it the answer? The OP clearly stated that they do not know the key 0. Of course there are many ways to work around that, but this answer doesn't show them. Also, I feel the fact that this answer is grammatically a question should be enough to skip the discussion. If you are not sure, use a comment to ask for more information first and then give an answer.

4wk_ Over a year ago

You become a bid childish, imho. I specified that I didn't know the index (in my example, 0). I'm sorry to irritating you.

|

monitaurus · Accepted Answer · 2013-04-26 15:22:34Z

2

Try this in PHP 5.4+ :

<?php
$a = array(array('foo' => 1111, 'bar' => 'example'));
print_r(current($a)['bar']);
?>

answered Apr 26, 2013 at 15:22

monitaurus

846 bronze badges

2 Comments

4wk_ Over a year ago

God, you're right : codepad.viper-7.com/fCiVWz Ok for PHP-5.4, that is great.

4wk_ Over a year ago

Yeah if there is no 'bar' key. But it is a notice - ok for me ! Both answer are good, so.

HamZa · Accepted Answer · 2013-04-26 15:30:13Z

1

Don't ask me how LOL:

$a = array(array('foo' => 1111, 'bar' => 'example'));
echo array_map(function($v){if(isset($v['bar'])){return $v['bar'];}}, $a)[0];

Note:

This works only with the latest versions of PHP 5.4+
This will throw an error if there isn't a "bar" key

Online demo.

Better solution:

$a = array(
    array('aaa' => 2222, 'bbb' => '333'),
    array('foo' => 1111, 'bar' => 'example'),
    array('wut' => 'lol', 'zzz' => 'ggg')
);

echo array_values(array_filter(array_map(function($v){if(isset($v['bar'])){return $v['bar'];}}, $a)))[0];

Online demo.

edited Apr 26, 2013 at 15:30

answered Apr 26, 2013 at 15:11

HamZa

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1 Comment

4wk_ Over a year ago

Yeah it's pretty good. But well, you us a local function ;) EDIT : Look @b4v answer : codepad.viper-7.com/fCiVWz

Your Common Sense · Accepted Answer · 2013-04-26 14:58:12Z

0

do you need something like this?

$c = $b[0]['bar'];

answered Apr 26, 2013 at 14:58

Your Common Sense

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Comments

Håkan · Accepted Answer · 2013-04-26 14:59:20Z

0

$a = array(array('foo' => 1111, 'bar' => 'example'));
echo $a[0]['bar'];

example

answered Apr 26, 2013 at 14:59

Håkan

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Comments

aynber · Accepted Answer · 2013-04-26 15:07:35Z

0

If you don't want to use [0], you can use this instead:

$value = null;
foreach($array as $each)
{
   if(isset($each['bar']))
      $value = $each['bar'];
}

answered Apr 26, 2013 at 15:07

aynber

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2 Comments

4wk_ Over a year ago

And I don't want a loop neither. ;)

aynber Over a year ago

Well, now you're just being difficult. :-P

Jocelyn · Accepted Answer · 2013-04-26 15:08:30Z

0

Use this code:

echo $array[0]['bar'];

Or, using PHP functions:

echo array_pop(array_shift($array));

It will extract the first element of $array:

Array
(
    [foo] => 1111
    [bar] => example
)

Then extract and display the last element of this array:

example

edited Apr 26, 2013 at 15:08

answered Apr 26, 2013 at 15:01

Jocelyn

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