finding indexes of an element

Question

this = '['123','231','34','123','34','123']'
dups = collections.defaultdict(list)
for i, item in enumerate(this):
    for j, orig in enumerate(seen):
        if item == orig:
        dups[j].append(i)
        break

    else:
        seen.append(item)

I have this code. What I want to do is to print out the indexes of each element so its in the form [('123',[0,3,5]),('231',[1]),('34',[2,4])] however my code produces [('123',[3,5]),('34',[4])] Is there anyway I can edit my code so it produces the answer I want without changing the form of the array so the output will stay as [('123',[0,3,5]),('231',[1]),('34',[2,4])]

234 is not in your list 'this' and you have '' around your list — Yoriz
– Yoriz, Commented Apr 27, 2013 at 14:34

Ashwini Chaudhary · Accepted Answer · 2013-04-27 14:35:11Z

3

Something like this:

In [35]: lis=['123','231','34','123','34','123']

In [36]: from collections import defaultdict

In [37]: dic=defaultdict(list)

In [38]: for i,x in enumerate(lis):
   ....:     dic[x].append(i)
   ....:     

In [40]: dic.items()
Out[40]: [('123', [0, 3, 5]), ('231', [1]), ('34', [2, 4])]

answered Apr 27, 2013 at 14:35

Ashwini Chaudhary

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