having trouble of sorting list in python

Question

a=[(' ', '000'), ('\n', '001000'), ('v', '00100100'), ('O', '0010010100'),('e', '110'), ('n', '1110'), ('r', '1111')]

and i want to sort the list first by the length of the number and then for the alphabetical order of all character that have the same length of number. i have tried to sort by for loop but it just sorts my length of number and not for alphabetical order.

a=[(' ', '000'), ('\n', '001000'), ('v', '00100100'), ('O', '0010010100'),('e', '110'), ('n', '1110'), ('r', '1111')]
for i in range (len(a)):
    for j in range(1,len(a)):
        if len(a[i][1])>len(a[j][1]):
            swap = a[i]
            a[i]=a[j]
            a[j]=swap

does anyone have any idea ??? thanks in advance

Is this for a class? Python has a few sort methods built in. — squiguy
– squiguy, Commented Apr 29, 2013 at 6:02

Blender · Accepted Answer · 2013-04-29 06:03:06Z

4

Use the key argument to sort:

a.sort(key=lambda item: (len(item[1]), item[0]))

Or more verbosely:

def sort_func(item):
    return len(item[1]), item[0]

a.sort(key=sort_func)

answered Apr 29, 2013 at 6:03

Blender

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2 Comments

Blender Over a year ago

@TommyNgo: See if the more verbose way of writing it helps.

Blender Over a year ago

@TommyNgo: I'm not sure how else to explain it. It sorts each element by using the output of sort_func(element) instead of the element itself.

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