Python 3 inheritance same as in C++

I have:

class A:

    def __init__(self):
        pass

    def func_X(self):
        print("Class A: X")

        self.func_Y()

    def func_Y(self):
        print("Class A: Y")
        print("Why does not work?")


class B(A):

    def __init__(self):
        A.__init__(self)

    def func_Y(self):
        print("Class B: Y")


if __name__ == "__main__":

    TEST = B()
    TEST.func_X()

OUTPUT:

Class A: X
Class B: Y

Question: Why works "B.func_Y", but not "A.func_Y"? This is bug? How to fix it? I need this to work same as in C++. C++ analog:

#include <iostream>

using namespace std;

class A
{
public:
      void func_X() {cout<<"Class A: X"<<endl; func_Y();}
      void func_Y() {cout<<"Class A: Y"<<endl;}
};

class B: public A
{
public:
      void func_Y() {cout<<"Class B: Y"<<endl;}
};


int main(void)
{
    B TEST = B();
    TEST.func_X();

    return 0;
}

OUTPUT:

Class A: X
Class A: Y

I faced this problem for a long time, but have not found a solution. Any idea how to solve this problem?