android/java: cannot parse existing XML file? (mac)

Question

I am making a simple android application and I am having issues parsing a simple XML file. I get the FileNotFoundException even through the file exists and I have all the permissions for it. I tried to modify the path in all the possible ways but I always get this exception thrown.

here's my code in the main activity:

protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

Engine engine = new Engine();
engine.parse();

}

in the engine class:

 public void parse() {
            try {

                File fXmlFile = new File("/res/XML/users.xml");
                if (!fXmlFile.exists()) {
                    throw new FileNotFoundException("Failed to find file: " + 
                            fXmlFile.getAbsolutePath());
                    }
DocumentBuilderFactory dbFactory = DocumentBuilderFactory
                    .newInstance();
            DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
            Document doc = dBuilder.parse(fXmlFile);
    ...

it really looks simple but I can't get this to work. any idea of what I'm doing wrong?

So did I understand correctly, the file is not found? I'm just wondering can you point to files outside of the emulator like you're trying to - or should the xml file reside within emulator file structure instead. — harism
– harism, Commented May 5, 2013 at 14:11
where can you see /Users/jon___davis/Desktop/users.xml on your device or simulator? — bakriOnFire
– bakriOnFire, Commented May 5, 2013 at 14:12
pasted the wrong string. the file is in res/XML but the situation doesn't change.. — Lorenzo
– Lorenzo, Commented May 5, 2013 at 14:16

Michal Palczewski · Accepted Answer · 2013-05-05 14:27:47Z

2

In order to get a file out of the Resources you can use one of two calls.

Check out. http://developer.android.com/reference/android/content/res/Resources.html

You can use context.getResources().openRawResource(R.xml.users)

This will return an input stream allowing you to read the file.

Alternatively you can call context.getResources().getXml(R.xml.users)

This will return an XML Resource parser, this is a pullParser that will allow you to parse the xml.

answered May 5, 2013 at 14:27

Michal Palczewski

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