Passing a variable through a function when passing to a function

Question

I'm not really sure what this is called or how to search for it so hopefully this hasn't been asked too many times before.

Is it possible to pass a variable to a function inside the function variable thing... I know that doesn't make sense, so here is an example:

sendContact('Firstname Lastname', $email, $address);

function sendContact(splitWord($name), $email, $address) {
    //code here
    print_r($name);
    //result array[0] = 'Firstname';
    //result array[1] = 'Lastname';
}

function splitWord($name) {
    //code here to split words
    return $result
}

All I'm looking for is the sendContact(splitWord()) part. Is there a way to do that as that doesn't seem to work.

nope, but you can just call splitWord() inside of sendContact() — user557846
– user557846, Commented May 8, 2013 at 3:06

Pascal Aschwanden · Accepted Answer · 2013-05-08 03:05:51Z

1

Yes. Don't put the function call in the definition, put it in the execution like so:

function sendContact( $name, $email ) {

}
function splitWord( $name ) {
  return $result;
}

sendContact( splitWord( $name ) );

answered May 8, 2013 at 3:05

Pascal Aschwanden

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1 Comment

LeeR Over a year ago

Of course.. Wow, I can't believe this didn't cross my mind. It must be that time of day.

BlitZ · Accepted Answer · 2013-05-08 03:12:08Z

1

Why not just remove some job from you?

sendContact('Firstname Lastname', $email, $address);

function sendContact($name, $email, $address) {
    $name = splitWord($name); // put inside to not duplicate for each call

    //code here

    print_r($name);

    //result array[0] = 'Firstname';
    //result array[1] = 'Lastname';
}

function splitWord($name) {
    //code here to split words
    return $result;
}

answered May 8, 2013 at 3:12

BlitZ

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Comments

Daryl Gill · Accepted Answer · 2013-05-08 03:11:28Z

0

Perhaps you could call your other function during the call for your main.. See an example:

function sendContact($name, $email, $address) {
    //code here
    print_r($name);
    //result array[0] = 'Firstname';
    //result array[1] = 'Lastname';
}

function splitWord($name) {
    //code here to split words
    return explode (" ",$name); // Different, but made to prduce an array to show that it works
}

sendContact(splitWord('Firstname Lastname'), $email, $address);

I have called the splitWord() function during the same time as i'm calling the sendContact(); function

answered May 8, 2013 at 3:11

Daryl Gill

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Comments

Plipus Tel · Accepted Answer · 2013-05-08 03:30:11Z

0

If you are 'real programmer', it's bad practice writing code like that. You should use OOP approach, if there are lots of functions involved inside a function.

class Email
{

    function splitWord($name)
    {
         // the jobs of split
    }

    function sendContact($name, $email, $address)
    {
         $receiver = $this->split($name);
         mail($receiver, $email, $address);
    }
}

answered May 8, 2013 at 3:30

Plipus Tel

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2 Comments

BlitZ Over a year ago

"real programmer" not puting objects everywhere. OOP is good when it needed, not forced. "OOP just for OOP" is not good.

LeeR Over a year ago

Those were just examples. The splitWord function is not specific only to the sendContact function. I just put them there to give context to what I was trying to achieve. Thanks though.

Paul Roub · Accepted Answer · 2013-05-08 03:05:40Z

-1

Not really. The most straightforward solution might be a simple wrapper function:

function sendAndSplitContact($name, $email, $address) {
  return sendContact(splitWord($name), $email, $address);
}

answered May 8, 2013 at 3:05

Paul Roub

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