for ( j = 0; j < d1; j++ ){
m += j;
for ( i = 0; i < d1*d2; i +=d2){
cout << *(m+i);
}
cout << endl;
}
d1,d2 are array dimensions
and
int* m = new int [d1*d2];
I want to traverse over my array and simply group and print the columns.Can't figure what's wrong with this code.Seems to be working fine untill the 3rd iteration in the following example:
Let's say my input values are 1 2 3 4 5 6 7 8 9
I get:
1 4 7
2 5 8
4 7 (something random)
In
m += j;
you are first incrementing m by 0, then by one, then by 2. If we originally took a copy
int *start = m;
then in the first iteration of the outer loop, we'd have
m == start
in the second,
m == start + 1
in the third
m == start + 3
You'd want m == start + 2 there. Except that you want to keep m in order to delete it at the end, so you shouldn't change m at all but use something like
for ( j = 0; j < d2; j++ ){
for ( i = j; i < d1*d2; i +=d2){
cout << *(m+i);
}
cout << endl;
}
*(m+i+j) could also access out-of-bounds, so I fixed that too now.m = &a[0];
for ( j = 0; j < d1; j++ )
{
for ( i = 0; i < d2; i++)
cout << *m++;
cout << endl;
}
