This is what I have, currently. Is there any nicer way to do this?
import struct
def int32_to_uint32(i):
return struct.unpack_from("I", struct.pack("i", i))[0]
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3 Answers
Not sure if it's "nicer" or not...
import ctypes
def int32_to_uint32(i):
return ctypes.c_uint32(i).value
8 Comments
Cairnarvon
That returns a Python integer type, though, which probably isn't a meaningful result in this context, as it isn't actually a uint32 anymore. I suppose it depends on how he's using it.
martineau
@Cairnarvon: For
1 and -1, the OP's version returns an int and a long respectively. My version returns a long for both.
Claudiu
Nice! I'd probably prefer this. Is this as cross-platform as
struct?martineau
@Claudiu: As for cross-platformness, all I can say is I think so.
martineau
@Claudiu: FWIW, in Python 3.3 both your and my version return
int for both cases. Also, what's the basis of your preference? You've never said what sort of nicer you're after. |
using numpy for example:
import numpy
result = numpy.uint32( numpy.int32(myval) )
or even on arrays,
arr = numpy.array(range(10))
result = numpy.uint32( numpy.int32(arr) )
Comments
I just started learning python, but something simple like this works for values in the range of a signed 32-bit integer
def uint(x):
if x < 0:
return hex(0xffff_ffff - abs(x) + 1)
else:
return hex(x)
2 Comments
GoldenretriverYT
why would you EVER need an unsigned int in the range of a signed int?
Darrel Lee
There are a lot of scenarios where you want to cast signed to unsigned. Sometimes its necessary when working directly registers on hardware device. If I remember correctly what I was doing at the time is that I wanted the hex representation for display purposes. If you, said print(x) you got -1, but I wanted to show the twos-complement hex value of 0xFFFF_FFFF.