shell grep command to pick only particular string

Question

I have a file with the following contents

abc_cde_app_13.5.0.10
abc_cde_app_13.5.0.10.xml
abc_cde_app_13.5.0.10_log.url
abc_cde_app_13.5.0.10_note.xml

The numbers may change and are not standard. And I wish to pick only the 1st one. I am passing all three in to the variable $file. But its showing Version found for all three files. How can I get it only for the 1st

if echo "$file" | grep -E "abc_cde_APP"; then
     echo "Version found: $file"
else
 echo "File not found"

Kent · Accepted Answer · 2013-05-10 15:44:40Z

1

how about this:

grep 'abc_cde_app_[^_]*$'

it works for your example:

kent$  echo "abc_cde_app_13.5.0.10
abc_cde_app_13.5.0.10_log.url
abc_cde_app_13.5.0.10_note.xml"|grep 'abc_cde_app_[^_]*$'   
abc_cde_app_13.5.0.10

answered May 10, 2013 at 15:44

Kent

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2 Comments

Jill448 Over a year ago

Hi,It worked n,But there is one more file abc_cde_app_13.5.0.10.xml Its picking that also. Sorry I didnt mention it before..I will update my question as well

Prince John Wesley Over a year ago

Try this :^abc_cde_app_[0-9.]*$

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