Converting input to a double in Java 1.4.2

Question

there is a section in a school project where I need to convert input to a double, to be multiplied by another double, and I keep getting "error: int cannot be dereferenced" for the following code:

        int a = Integer.parseInt(input.readLine());
        int aa = a.nextInt();
        int aaa = Math.pow(1 + a, aa);
        amount1 = (aaa * 13.49);
        amount += amount1;

Any ideas as to what I'm doing wrong?

An int is a primitive, not an object. This means you cannot call methods on it. — Peter Lawrey
– Peter Lawrey, Commented May 10, 2013 at 18:45

rgettman · Accepted Answer · 2013-05-10 17:51:07Z

1

You cannot call a method on an int, but you are trying:

a.nextInt();

Assuming that input is a Scanner, I think that you want to call nextInt on input instead.

EDIT

Scanner didn't exist in 1.4.2, so just do for aa what you already did for a -- parse the next line of input.

edited May 10, 2013 at 17:51

answered May 10, 2013 at 17:45

rgettman

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10 Comments

Frisbee68 Over a year ago

How do I fix this? I am new to Java.

Smit Over a year ago

Hint: Use the same for aa as you used for a

Frisbee68 Over a year ago

Also I can't use scanner, because I have to use Java 1.4.2, so instead I'm using BufferedReader

Hot Licks Over a year ago

@user1965245 - You need to read the line into a String and then break it apart into successive pieces. Apply parseInt to the pieces, not the entire string.

Hot Licks Over a year ago

(And you can use String.split to break the line apart.)

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Mark S · Accepted Answer · 2013-05-10 17:56:53Z

0

Difficult to understand without knowing the format you are reading: e.g If your input source has a single integer per line - simply repeat the first line

int aa = Integer.parseInt(input.readLine());

answered May 10, 2013 at 17:56

Mark S

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