Can any one tell what wrong with this script ?. Because I am getting the error like
./timer: line 9: [13: command not found
./timer: line 12: [13: command not found
My script look like
#!/bin/bash
while :
do
HOUR=$(date +%H)
MINUTE=$(date +%M)
SECOND=$(date +%S)
if [$HOUR == 13] && [$MINUTE == 12] && [$SECOND == 1]
then ./binary
elif [$HOUR == 18] && [$MINUTE == 30] && [$SECOND == 1]
then ./binary
fi
done
put a space between the [ ... ] Example:
if [$HOUR == 13] && [$MINUTE == 12] && [$SECOND == 1]
Should become
if [ $HOUR == 13 ] && [ $MINUTE == 12 ] && [ $SECOND == 1 ]
== isn't POSIX, the correct operator to compare string is =. However, we don't wan't to compare strings but integers, so we shall use -eq instead. Take a look at my answer for more information.I think you must use "${VARIABLE}" and respect spaces for square brackets
This would give :
if [ "${HOUR}" == 13 ] && [ "${HOUR}" == 12 ] && [ "${HOUR}" == 1 ]
Hope that helps !
the test operators in bash need to have a space by the opening and closing bracket, try
[ $HOUR == 13 ] && [ $MINUTE == 12 ] && [ $SECOND == 1 ]
and
[ $HOUR == 18 ] && [ $MINUTE == 30 ] && [ $SECOND == 1 ]
here is a link that you might find useful http://tldp.org/LDP/abs/html/testconstructs.html
Several things:
[ and before ].-eq operator to compare numeric values (see Bash conditional operators).Like so:
if [ "$HOUR" -eq 13] && [ "$MINUTE" -eq 12 ] && [ "$SECOND" -eq 1 ]
elif [ "$HOUR" -eq 18 ] && [ "$MINUTE" -eq 30 ] && [ "$SECOND" -eq 1 ]
