cout print string variable cannot pass the build

Question

Could any one help me to figure out which the following code cannot build successfully:

#include <iostream>

int main(void){

    std::string str1("sfsfasfdsdf");
    std::cout << str1 << std::endl;
    return 1;
}

Thanks.

What is error your compiler is giving you?

Shafik Yaghmour
– Shafik Yaghmour

2013-05-22 15:53:52 +00:00
Commented May 22, 2013 at 15:53 — Shafik Yaghmour
– Shafik Yaghmour, Commented May 22, 2013 at 15:53

taocp · Accepted Answer · 2013-05-22 15:57:21Z

5

You have to include std::string header:

#include <string>

EDIT: According to @ShafikYaghmour's comments, include iostream sometimes brings in string, but it may not be the case for you if you only have the posted code.

edited May 22, 2013 at 15:57

answered May 22, 2013 at 15:52

taocp

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6 Comments

taocp Over a year ago

@ShafikYaghmour Would you please provide source of that? I never realized that this is the case, at least not on Windows.

syam Over a year ago

@ShafikYaghmour: this is implementation-specific. Some do, others don't, the Standard doesn't mandate anything.

Shafik Yaghmour Over a year ago

@syam I did not say the standard required it, I said depends, I am not sure we have enough information. Although it is a good guess. On ideone it build fine: ideone.com/xoChjb

hetepeperfan Over a year ago

I think is better and more clear if you specify the headers of the objects in the source file you are using them.

taocp Over a year ago

@user1655685 You are welcome. Glad it helped. You may accept my answer by clicking on the \/ sign besides my answer.

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