Passing an object to a function

Question

I want to pass an object to the function flipIt(obj). I have the image id stored in a variable called globe.

When I pass globe to flipIt(), it isn't working because globe is a variable containing the image id and flipIt() needs an object.

I have tried ('#'+globe) to make it obj but its is also not working:

flipIt('#'+globe);

Function Definition is:

function flipIt(obj) {
    console.log("value before Function status   " + status);
    alert('FlipIT Called' + obj);

    $(obj).css("-webkit-transform-style","preserve-3d");
    $(obj).css("-webkit-transition","all 1.0s linear");
    $(obj).css("transform-style","preserve-3d");
    $(obj).css("transition","all 1.0s linear");
}

I tried by printing obj value... for variable it is printing id value instead it should print HTMLimage element.

Javascript

$(document).ready(function () {
    var globe;

    /*   Reading the data from XML file*/
    $.ajax({
        type: "GET",
        url: "photos.xml",
        dataType: "xml",
        success: function(xml) {
            $(xml).find('item').each(function() {
                var path = $(this).attr('path');
                var width = $(this).attr('width');
                var height = $(this).attr('height');
                var id = $(this).attr('id');
                var alt = $(this).attr('alt');
                var longdesc = $(this).find('longdesc').text();
                var description = $(this).find('desc').text();
                $('#myImageFlow').prepend('<img src="'+path+'" id='+id+'  height="'+height+'"  width="'+ width+'" longdesc="'+longdesc+'" alt="'+alt+'"/>');
                imgArr[i] = description;
                i = i+1;
            });
        });
    });
});

XML File:

<items id = "items">
   <item path="img/1_bankofamerica.jpg" width="300" height="360" id="id1" alt="img1" type="bitmapfile">
      <back>swf/backcard_0.swf </back>
      <longdesc>img/img1.png</longdesc>
      <desc>Decription about Image # 1 </desc>
   </item>
   <item path="img/2_harbourfront.jpg" width="300" height="360" id="id2" alt="img2" type="bitmapfile">
      <back>swf/backcard_1.swf </back>
      <longdesc>img/img2.png</longdesc>
      <desc>Decription about Image # 2 </desc>
   </item>
   <item path="img/2_harbourfront3.jpg" width="300" height="360" id="id3" alt="img3" type="bitmapfile">
      <back>swf/backcard_2.swf </back>
      <longdesc>img/img3.png</longdesc>
      <desc>Decription about Image # 3 </desc>
   </item>
   <item path="img/3_harbourfront.jpg" width="300" height="360" id="id4" alt="img4" type="bitmapfile">
      <back>swf/backcard_3.swf </back>
      <longdesc>img/img4.png</longdesc>
      <desc>Decription about Image # 4 </desc>
   </item>
   <item path="img/5_lighthouse.jpg" width="300" height="360" id="id5" alt="img5" type="bitmapfile">
      <back>swf/backcard_4.swf </back>
      <longdesc>img/img5.png</longdesc>
      <desc>Decription about Image # 5 </desc>
   </item>
</items>

I would say, pass $('#'+globe), but I see you're already doing this inside the flipIt function. Why do you access globe again in the flipIt function if you want to pass it? — huysentruitw
– huysentruitw, Commented May 23, 2013 at 11:07
was just checking globe.. i am not accessing globe inside function — anam
– anam, Commented May 23, 2013 at 11:08
What does this mean? "i have obj value stored in a variable 'globe'" You're using globe as if it's a string not an object. — Rup
– Rup, Commented May 23, 2013 at 11:09
show content of globe, and show the HTML code that contains the element with that id.. — huysentruitw
– huysentruitw, Commented May 23, 2013 at 11:09

huysentruitw · Accepted Answer · 2013-05-23 12:06:58Z

3

Asuming globe is a string containing the id of the element you want to select (not prefixed with #), you'll need to transform it into a jQuery object before passing it to your function:

flipIt($('#'+globe));

Then, you don't need to wrap another $() around it inside the flipIt function, because it's already an object. So inside the function, just do:

obj.css("-webkit-transform-style","preserve-3d");
...

Next, I guess you want to declare globe in the global scope. Now you're declaring it in the scope of the document ready function. So put it outside:

var globe;

$(document).ready(function () {
    // document ready
});

Also the document ready has a shorter notation:

$(function() {
    // document ready
});

edited May 23, 2013 at 12:06

answered May 23, 2013 at 11:12

huysentruitw

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