Adding layout properties dynamically

Question

I have added a LinearLayout dynamically and a TextView into it. Now I have to add the background, format them as per my requirement. So I am stuck with few questions. Here is my code:

LinearLayout parentLayout = (LinearLayout) findViewById(R.id.master);
LinearLayout Linear1 = new LinearLayout(this);
Linear1.setOrientation(LinearLayout.HORIZONTAL);
Linear1.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT,
        LayoutParams.MATCH_PARENT));
Linear1.setId(1);
TextView tvLeft = new TextView(this);
tvLeft.setText("Hello");
tvLeft.setLayoutParams(new LayoutParams(LayoutParams.MATCH_PARENT,
        LayoutParams.WRAP_CONTENT));
Linear1.addView(tvLeft);
parentLayout.addView(Linear1);

I have few questions:

How can I add drawable resource as my background?

I have tried this:

Linear1.setBackgroundResource(getResources().getDrawable(R.drawable.gradient_pink));

I am getting error message by the compiler as:

The method setBackgroundResource(int) in the type View is not applicable for the arguments (Drawable)

How to access the element whose id is set pragmatically?
How to set width = 0dip?

Please help me with these question.

Pragnani Kinnera · Accepted Answer · 2013-06-01 04:22:06Z

2

Try this

Linear1.setBackgroundResource(R.drawable.gradient_pink);

or

Linear1.setBackgroundDrawable(getResources().getDrawable(R.drawable.gradient_pink));

How to access the element whose id is set pragmatically?

with the findViewById(yourid) itself

answered Jun 1, 2013 at 4:22

Pragnani Kinnera

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2 Comments

NewUser Over a year ago

setId takes only integers. I have written setId(1) what should I write in findViewById?

Pragnani Kinnera Over a year ago

findViewById also accepts int only... you should give findViewById(1)

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