I am trying to use this awk command:
awk -F: '
FILENAME==ARGV[1] {
a[FNR]=$1
}
FILENAME==ARGV[2] {
for(i=1;i<=length(a);i++) {
if(match($0,a[i])) {
print a[i],$1
}
}
}' 16.passwd 16.group | sort
But got:
awk: line 1: illegal reference to array a
Your problem is this:
length(a)
Using length(array) to get the number of elements in an array is a GNU awk extension and apparently you aren't using GNU awk. Change:
for(i=1;i<=length(a);i++)
to
for(i=1;i in a;i++)
and it should work.
length only for strings, not arrays. However, like Gawk, BSD Awk also implements it for arrays, and so does Mawk since v1.3.4 (whereas Mawk v1.3.3 and below resulted in the error seen by the OP).for (k in a) ++count.I got this issue. Script worked on old server and stop to work on a new one.
Issue was that old server had 'gawk' installed, and new one has 'mawk', which does not support arrays.
I solved it by sudo apt-get install gawk.
mawk installed. The issue was with length(array). See the other answer.I did not see anything wrong with your script, as far as syntax goes. I saved your code in a file called script.awk, and executed:
awk -F: -f script.awk file1 file2
and did not see any error. Why don't you try the same: put your script in a separate file and invoke awk on it. If you still have the same problem, I suspect the problem might be in the data file.
I cleaned up the code a little, the new version may be easier to read:
FNR==NR {a[FNR] = $1; next}
{
for (i in a) {
if (match($0, a[i])) {
print a[i], $1
}
}
}
if (!a) …, which is essentially the same issue.