node.js / Socket.timeout(number)

Question

I wrote the next code:

socket.setTimeout(2000);
socket.on('timeout', function() {   
    console.log("Timeout");
});
    socket.on('data', function(data){})

I send a data to my socket, but when I finish to send this data, the timeout doesn't occuer.

There is no socket.end() in my code.

Joachim Isaksson · Accepted Answer · 2013-06-06 17:25:12Z

1

The easiest way is to pass the timeout callback as a method straight to setTimeout where it will be added as a one-time listener to 'timeout';

socket.setTimeout(2000, function() {  
    console.log("Timeout");
});
socket.on('data', function(data){})

I've never seen the syntax of listening to the '' event before (I probably missed something), but the event for a timeout if you want to listen with it using on should be called 'timeout'.

answered Jun 6, 2013 at 17:25

Joachim Isaksson

182k28 gold badges298 silver badges308 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

user2450886 Over a year ago

Yes, I correct the last issue. I try your idea, but its still the same.

Joachim Isaksson Over a year ago

@user2450886 Sounds like there may be something not showing in your displayed code that's preventing the event from triggering. Sadly hard to debug then :-/

user2450886 Over a year ago

There is other command which close the socket besides socket.end() and socket.destroy()? As I understand, socket.write doesn't close the socket.

Joachim Isaksson Over a year ago

@user2450886 No, it shouldn't close unless there's an error transmitting the data, in which the error handler should be invoked.

Collectives™ on Stack Overflow

node.js / Socket.timeout(number)

1 Answer 1

4 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

4 Comments

Your Answer

Sign up or log in

Post as a guest

Related