What is the difference between
System.arraycopy(),clone()- manual copying by iterating through the elements
Arrays.copyOf()- and just doing
arraynew = arrayold?
System.arraycopy() uses JNI (Java Native Interface) to copy
an array (or parts of it), so it is
blazingly fast, as you can confirm
here;clone() creates a new array with the same characteristics as the old array, i.e., same size, same type, and same contents. Refer to here for some examples of clone in action;manual copying is, well, manual copying. There isn't much to say about this method, except that many people have found it to be the most performant.arraynew = arrayold doesn't copy the array; it just points arraynew to the memory address of arrayold or, in other words, you are simply assigning a reference to the old array.arraycopy was written in 2006. clone could (in theory, and should for obvious reasons) be specially treated by the runtime to perform exactly a memcpy. The memcpy is followed by a pass to clear the "lock" bit in the header of each array element. There's no reason why arraycopy and clone should perform differently.arraycopy can be special-cased just the same as clone. @JG: all of those ways create shallow copies (except maybe manually copying, depending on how it's done).arraycopy has unnecessary overhead due to initializing the elements of the target array followed by immediately writing back over them. clone should be the fastest because it wouldn't have to initialize memory. cloneRange would be fastest overall by allocating uninitialized memory and shallow copying an array subrange into it. All of the above should be implemented by the runtime itself, which means no JNI (lower than the JNI - the JIT could detect these calls and handle them with machine code).System.arraycopy() copies data from one existing array into another one and depending on the arguments only copies parts of it.clone() allocates a new array that has the same type and size than the original and ensures that it has the same content.System.arraycopy(), but is more code and therefore a bigger source for errorsarraynew = arrayold only copies the reference to the array to a new variable and doesn't influence the array itselfThere is one more useful option:
Arrays.copyOf() can be used to create a copy of another array with a different size. This means that the new array can be bigger or larger than the original array and the content of the common size will be that of the source. There's even a version that makes it possible to create an array of a different type, and a version where you can specify a range of elements to copy (Array.copyOfRange()).
Note that all of those methods make shallow copies. That means that only the references stored in the arrays are copied and the referenced objects are not duplicated.
System.arraycopy() compared to .clone()?There are answers but not a complete one.
The options considered are
Below is the java implementation of Arrays.copyOf()
public static double[] More ...copyOf(double[] original, int newLength) {
double[] copy = new double[newLength];
System.arraycopy(original, 0, copy, 0,
Math.min(original.length, newLength));
return copy;
}
As you can see copyOf uses System.arraycopy internally.
Note: There is no point in comparing the speed obviously because their functionalities differ.