How to access Json Attribute which has space in its name

Question

Find below the json response...

{
"personalDetails": {
    "Name ": " Taeyeon",
    "Date Of Birth ": " 03/09/1989",
    "Zodiac ": " Pisces"
},
"education": {
    "High School ": " Jeonju Art High school ",
    "University ": " -"
}

}

My Class is here

    public class Biography
{
    public personalDetails personalDetails { get; set; }
    public education education { get; set; }
    public work work { get; set; }
    public personal personal { get; set; }
}


public class personalDetails
{
    public string Name { get; set; }
    public string DateBirth { get; set; }
    public string Zodiac { get; set; }
}

public class education
{
    public string HighSchool { get; set; }
    public string University { get; set; }
}

Then I put the code:

Biography dataSet = JsonConvert.DeserializeObject<Biography>(e.Result);

It doesn't work because of Arttribute has space. What should I do?

Sean Kenny · Accepted Answer · 2013-06-07 12:09:52Z

12

Try adding the JsonProperty attribute. That should work for you.

[JsonProperty(PropertyName = "Date Of Birth ")]
public string DateBirth { get; set; }

[JsonProperty(PropertyName = "High School ")]
public string HighSchool { get; set; }

Edit

I see you have trailing spaces too so updated the attributes above. Do the same for "Name ", etc.

edited Jun 7, 2013 at 12:09

answered Jun 7, 2013 at 11:15

Sean Kenny

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Comments

user3486773 · Accepted Answer · 2017-03-17 15:57:08Z

0

Download the Json as a string, and use something like myString = myString.Replace(@"High School", "HighSchool"). Do this as the step before deserializing.

answered Mar 17, 2017 at 15:57

user3486773

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Comments

Mayer Spitz · Accepted Answer · 2019-02-12 20:51:00Z

0

For some people this might be helpful:

Add Namespace: using Newtonsoft.Json;

var jsonString = "{" +
    "'personalDetails': {" +
        "'Name ': 'Taeyeon'," +
        "'Date Of Birth ': ' 03/09/1989'," +
        "'Zodiac ': ' Pisces'," +
    "}," +
    "'education': {" +
        "'High School ': ' Jeonju Art High school '," +
        "'University ': ' -'," +
    "}" +
"}";

var json = JsonConvert.DeserializeObject(jsonString);            
return Ok(json);

answered Feb 12, 2019 at 20:51

Mayer Spitz

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