parsing xml tags in a specific order in python

Question

I want to load some tags with a specified order from an xml file into python as below:

<data>
    <testset name="ts1" order="1" descrption="this is ts1 descrption">
        <testcase name="tc1" order="1" />
        <testcase name="tc2" order="2" />
    </testset>

    <testset name="ts2" order="2" descrption="this is ts2 descrption">
        <testcase name="tc3" order="1" />
        <testcase name="tc4" order="2" />
    </testset>
</data>

The way that I know is ugly so please let me know if there is a better way:

class TS():
    def __init__(self, name, order):
        self.name = name
        self.order = order

import xml.etree.ElementTree as ET
def parseXML():
    ts_arr = []
    tree = ET.parse('test_specs.xml')
    root = tree.getroot()
    for testset in root.iter('testset'):
        i = 0
        while i<len(ts_arr):
            if testset.get('order')<ts_arr[i].order:
                        ts_arr.append(i, TS(testset.get('name'),testset.get('order')))
                        break
            i += 1

... and the same for testcases

Martijn Pieters · Accepted Answer · 2013-06-07 23:13:14Z

1

Sort the test sets by their order attribute:

root = tree.getroot()
testsets = root.findall('testset')

for testset in sorted(testsets, key=lambda ts: int(ts.attrib['order'])):
    # test sets are looped over in the order specified in the `order` attributes
    testcases = testset.findall('testcase')
    for testcase in sorted(testcases, key=lambda ts: int(ts.attrib['order'])):
        # test cases are looped over in the order specified

edited Jun 7, 2013 at 23:13

answered Jun 7, 2013 at 23:04

Martijn Pieters

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1 Comment

max Over a year ago

Wonderful. 100% bang on. Thanks.

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