Java: parsing file path

Question

I need to parse a file path to get the filename from it. What confuses me is that windows uses \ as the delimeter and linux - / and somehow the provided filepath can even contain both delimeters at the same time.

Of course I can do:

int slash = filePath.lastIndexOf("/");
int backslash = filePath.lastIndexOf("\\");
fileName = filePath.substring(slash > backslash ? slash : backslash);

but is there a better way in case I have more delimiters? (probably not for a file path)

File f = new File(fileName); String name = f.getName();

Andrew Thompson
– Andrew Thompson

2013-06-10 10:36:20 +00:00
Commented Jun 10, 2013 at 10:36 — Andrew Thompson
– Andrew Thompson, Commented Jun 10, 2013 at 10:36

Duncan Jones · Accepted Answer · 2013-06-10 10:36:33Z

9

Just use the File class:

String fileName = new File(path).getName();

It handles forward and backwards slashes, plus combinations of the two.

answered Jun 10, 2013 at 10:36

Duncan Jones

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LuigiEdlCarno · Accepted Answer · 2013-06-10 10:43:08Z

0

You can use

String separator =System.getProperty("path.separator");

to get you systems separator.

answered Jun 10, 2013 at 10:43

LuigiEdlCarno

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1 Comment

svz Over a year ago

This won't do as there may be both separators at the same time.

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