Conversion Enum to Boolean type

Question

In my application i want to represent AND as 1 , and OR as 0, instead of opting for #define method , i am using enum to represent them , as shown in the below example program

#include <stdio.h>

enum gateConnection_t
{AND,OR}
gateConnection;

int main()
{

bool and_t = AND;
bool or_t = OR;

printf("%d\n",and_t);
printf("%d\n",or_t);

return 0;
}

As seen above , i am directly assigning the enum values to boolean vvariables. The program works as expected and my only question is whether the internal cast done is safe , or is it better to use explicit casting such as static_cast ?

What's the point of this?

idoby
– idoby

2013-06-11 13:34:56 +00:00
Commented Jun 11, 2013 at 13:34 — idoby
– idoby, Commented Jun 11, 2013 at 13:34
@mwerschy c++ , sorry for tagging C

CodeCrusader
– CodeCrusader

2013-06-11 13:37:29 +00:00
Commented Jun 11, 2013 at 13:37 — CodeCrusader
– CodeCrusader, Commented Jun 11, 2013 at 13:37

Bathsheba · Accepted Answer · 2013-06-11 13:34:07Z

3

For starters, your {AND,OR} are the wrong way round.

Enums by standard start at 0 (although you can override that).

Use

enum gateConnection_t
{OR,AND}

instead.

The cast is safe by the way.

Conceptually though it's a nasty thing to do. Why do you want this; particularly in C++? What's wrong with true and false?

answered Jun 11, 2013 at 13:34

Bathsheba

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1 Comment

CodeCrusader Over a year ago

yes , it was intended as an enum with AND = 0....I have to do this to represent relationship between two signals , the decision to use 1 and 0 is abitrary , with no particular reason

aah134 · Accepted Answer · 2013-06-11 13:37:14Z

1

enum gateConnection_t
{AND=1,OR=0}
gateConnection;

or

enum gateConnection_t
{
OR=0,
AND  //<== this equal to the previous plus one automatically 
}gateConnection;

answered Jun 11, 2013 at 13:37

aah134

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