How to run function on first object?

Question

I've got this function which runs for each instance of 'fullName':

$(xml).find("fullName").each(function(){ ... });

But there is really only ever one instance and I don't want to be using each, is there some other way to create this function without using each. Maybe just:

$(xml).find("fullName").it(function(){ ... });

Yes, use first(), or explain what function it is, and there might be a suitable jQuery method to use. — David Thomas
– David Thomas, Commented Jun 14, 2013 at 14:58
I mean, the function is rather unique, but does jQuery have a method for setting/ getting cookies? — Watson
– Watson, Commented Jun 14, 2013 at 15:00
This has been discussed here: stackoverflow.com/questions/4856938/…. — Jeremy Gallant
– Jeremy Gallant, Commented Jun 14, 2013 at 15:01
It might depend on what the Function is meant to be used for.. Ex: Do you wanna use a Simpe function expression or a whole function declaration... There might be several alternatives to achieving what you want.... Just try to Explain further — ErickBest
– ErickBest, Commented Jun 14, 2013 at 15:02

Lim H. · Accepted Answer · 2013-06-14 14:59:17Z

4

You can try something like this

var func = function(){ ... }
func.call($(xml).find("fullName")[0], args));

answered Jun 14, 2013 at 14:59

Lim H.

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Comments

Justin Helgerson · Accepted Answer · 2013-06-14 14:58:46Z

3

You could just reference by index:

$(xml).find("fullName")[0]

answered Jun 14, 2013 at 14:58

Justin Helgerson

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2 Comments

Watson Over a year ago

But where is the function?

thomasfedb Over a year ago

@Watson As the value you wish to use is directly accessible there is no need for a function. Of course, you could use a function if you liked. This is described by LimH's answer.

Philip Giuliani · Accepted Answer · 2013-06-14 14:59:49Z

1

Have a look at the .first() method

http://api.jquery.com/first/

answered Jun 14, 2013 at 14:59

Philip Giuliani

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1 Comment

nnnnnn Over a year ago

But how does that help the OP run a function? That just returns another jQuery object and he or she already has a jQuery object...

maximkou · Accepted Answer · 2013-06-14 15:10:05Z

1

var fnc = null;
if (typeof (fnc = $(xml).find("fullName").eq(0)) == 'function'){
    fnc(args);
}

edited Jun 14, 2013 at 15:10

answered Jun 14, 2013 at 15:00

maximkou

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4 Comments

nnnnnn Over a year ago

But how does that help the OP run a function? That just returns another jQuery object and he or she already has a jQuery object...

maximkou Over a year ago

@nnnnnn, add .call(arguments)

nnnnnn Over a year ago

So that's what your answer should say. With more detail. (Assuming it doesn't then become a duplicate of Lim H.'s answer.) But you don't need .eq(0) since the OP is confident that the .find() will only find one item anyway - that's the point of the question...

maximkou Over a year ago

@nnnnnn, I used to not trust the customer's data. Answer corrected.

ErickBest · Accepted Answer · 2013-06-14 15:08:51Z

0

What of:

(function($){
 $.fn.anotherFunction=function(){

alert('Handles for anotherFunction');
}
})(jQuery)

and call it like::

$(xml).find("fullName").anotherFunction();

is that what He Wants??

answered Jun 14, 2013 at 15:08

ErickBest

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Comments

Rui Jarimba · Accepted Answer · 2013-06-14 15:27:14Z

0

Or....

$(xml).find("fullName").first()

edited Jun 14, 2013 at 15:27

Rui Jarimba

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answered Jun 14, 2013 at 15:03

ErickBest

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1 Comment

nnnnnn Over a year ago

But (as I already asked about some other answers) how does that help the OP run a function? That just returns another jQuery object and he or she already has a jQuery object...

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