How to nest data in PHP array and access it with foreach()?

Question

foreach ($nav_items as $nav_href=>$nav_title=>$nav_class) {
    if ($pageHref == $nav_href) {
        echo '<li class="' . $nav_class .  'active">' . $nav_title . '</li>';
    } else {
        echo '<li class="' . $nav_class . '">' . $nav_title . '</li>';
    }
}

What is wrong with this code above? This corresponds to the array below.

$pageLoc = 'where';
$nav_items = array(
    'index'=>'Home'==>'', 
    'where'=>'Where?'==>'dropdown'==>'', 
    'appeals'=>'Current Appeals'==>'', 
    'news'=>'Latest News'==>'', 
    'events'=>'Events'==>'', 
    'dontate'=>'Dontate'==>'', 
);

I am basically trying to put an active class in front of the list item when it matches $pageLoc and when it doesn't just a simple <li class=""> BUT the dropdown menu item: 'where?' needs a <li class="dropdown"> always! and when it is active, it will be <li class="dropdown active">

all you'd need to do to figure out this won't work is ... run the code. you'll get an error that tells you exactly what's wrong (your syntax, in this case). — user428517
– user428517, Commented Jun 14, 2013 at 17:13

Marc B · Accepted Answer · 2013-06-14 17:06:13Z

2

You have a flat-out syntax error:

foreach ($nav_items as $nav_href=>$nav_title=>$nav_class) {
                                            ^^^^^^^^^^^^

The syntax is

foreach($array as $key => $value)

You cannot have => $value1 => $value2 etc....

answered Jun 14, 2013 at 17:06

Marc B

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2 Comments

Luke Over a year ago

Any ideas on how to go about solving my issue? I have a menu with active classes. But for one menu item, I need a dropdown class always to preside there.

ಠ_ಠ Over a year ago

$nav_href=>$nav_title in your foreach, then grab them from within the foreach loop

Software Engineer · Accepted Answer · 2013-06-14 17:10:05Z

0

You ca n have it as :

foreach ($nav_items as $nav_title=>$nav_class) {

  ....

}

What are you trying to check with $nav_href ?

answered Jun 14, 2013 at 17:10

Software Engineer

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2 Comments

Luke Over a year ago

It is for a navbar menu. So they all have normal <li></li>. When on that page, eg when $nav_href= 'current-page' the li class for that menu item will be 'active' and the others remain at <li>. My problem is, I have one menu item that requires a dropdown class always.

Software Engineer Over a year ago

Why dont you check this way ? if($pageLoc == $nav_class) because your $nav_class is the key in the key-value pair, and as seen from your array, 'where' appears to be the key.

amigura · Accepted Answer · 2013-06-14 17:39:44Z

0

your $nav_items is a pretty mess, not a correct array.

$pageLoc = 'where';
$nav_items = array('index'=>'Home==>', 'where'=>'Where?==>', 'appeals'=>'Current Appeals==>', 'news'=>'Latest News==>', 'events'=>'Events==>', 'dontate'=>'Dontate==>');


foreach ($nav_items as $nav_class=>$nav_title) {
   if ($pageLoc == $nav_href) {
         echo '<li class="' . $nav_class .  'active">' . $nav_title . '</li>';
   } 
   else {
       echo '<li class="' . $nav_class . '">' . $nav_title . '</li>';
   }
}

answered Jun 14, 2013 at 17:39

amigura

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Comments

zsawyer · Accepted Answer · 2013-06-14 18:07:11Z

There is no such syntax that makes it that easy. But here is what you probably want:

This is how you create a nested array which fits your needs:

$nav_items = array(
    array('href' => 'index',   'title' => 'Home',            'class' => ''), 
    array('href' => 'where',   'title' => 'Where?',          'class' => 'dropdown'), 
    array('href' => 'appeals', 'title' => 'Current Appeals', 'class' => ''), 
    array('href' => 'news',    'title' => 'Latest News',     'class' => ''), 
    array('href' => 'events',  'title' => 'Events',          'class' => ''), 
    array('href' => 'dontate', 'title' => 'Dontate',         'class' => ''),                
);

According to the above array structure this would be the foreach for you to use:

foreach ($nav_items as $item) {
    if ($pageHref == $item['href']) {
        echo '<li class="' . $item['class'] .  ' active">' . $item['title'] . '</li>';
    } else {
        echo '<li class="' . $item['class'] . '">' . $item['title'] . '</li>';
    }
}

DEMO FIDDLE

Here is 2 more notes:

Note1: In php5 you could work with objects and create a nav item class containing the information which is above only the simple array('href' => 'dontate', 'title' => 'Dontate', 'class' => '')

Note2: Your line

echo '<li class="' . $nav_class .  'active">' . $nav_title . '</li>';

will concatenate both classes to one. So this code would give you dropdownactive as the class. You need to insert a space before active, else CSS won't recognize both classes.

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