Running Functions in GUI matlab

Question

Continuing my struggle against GUI's, I have run into another road block.

Ive successfully created a button that opens a file as a string, and places it in a text box in my GUI like so.

 [filename, pathname] = ...
     uigetfile({'*.m';'*.mdl';'*.mat';'*.*'},'File Selector');

set(handles.Textbox1, 'string', fullfile(pathname,filename));

But now I cannot seem to use a function on the acquired file. Ive tried doing

  str = get(handles.Textbox1,'string');
Histogram(str); %Histogram is a function that I created.

But im getting the following errors

??? Error using ==> Histogram Too many input arguments.

Error in ==> VarunGUI>pushbutton2_Callback at 94 Histogram(str);

Error in ==> gui_mainfcn at 96 feval(varargin{:});

Error in ==> VarunGUI at 42 gui_mainfcn(gui_State, varargin{:});

Error in ==> @(hObject,eventdata)VarunGUI('pushbutton2_Callback',hObject,eventdata,guidata(hObject))

??? Error while evaluating uicontrol Callback

Is my code for calling the function to blame, or is the function itself? I'm having trouble understanding how to alter the function to work on the called image, so that may be my problem, the function begins with the following code.

function Histogram
clear;
clc;
fid = fopen('');
myimage = fread(fid, [512, 683], '*uint8');
fclose(fid);

Is there a certain variable I need to place in the '' to make the GUI act in the manner to which I would like it? Question ran a little long, but please tell me if there is anything else you need to see in order to assist me, any guidance or tips would be great. Thanks!

Have you tried using dbstop if error and figuring out where exactly strange things become visible? — Dennis Jaheruddin
– Dennis Jaheruddin, Commented Jan 3, 2014 at 16:27

m_power · Accepted Answer · 2013-06-18 17:01:32Z

3

Your Histogram function doesn't have an input, so it fails when you call it : Histogram(str)

answered Jun 18, 2013 at 17:01

m_power

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Schorsch · Accepted Answer · 2013-06-18 17:00:51Z

2

You're problem is that call Histogram and pass it str:

Histogram(str)

But you don't define Histogram to expect input:

function Histogram

What you need is something like this:

function Histogram(str)

% do something with str

answered Jun 18, 2013 at 17:00

Schorsch

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8 Comments

user2475404 Over a year ago

@schorsch Im not entirely sure how I would "definte Histogram to expect input" as you say.

Schorsch Over a year ago

@m_power ... debugging Matlab ... practice makes the master ;-)

Schorsch Over a year ago

@user2475404 : what do you expect Histogram to do with the str?

user2475404 Over a year ago

well the Histogram function was supposed to create a histogram with certain parameters.

Schorsch Over a year ago

@user2475404 : if you want to use the str variable in Histogram, just change the first line of your function definition along the lines of the third code-block in my answer.

|

Shaun314 · Accepted Answer · 2013-06-18 17:27:01Z

1

I got this y'all!

Change your histogram function to this: (literally copy and paste what's below)

function Histogram(str) %Add input argument
%clear %DO NOT USE CLEAR in a function, the benefit of using a function is you don't have to %clear anything :)
clc;
fid = fopen(str); %Use input argument
myimage = fread(fid, [512, 683]); %take off *uint8
fclose(fid);

Read MATLAB's documentation, it is fantastic, and would allow you to see why fread and uint8 don't go together in a matter of seconds (seriously less than 20 seconds would give you your answer) and it would also solve all your other extremely basic issues you are having.

answered Jun 18, 2013 at 17:27

Shaun314

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2 Comments

Schorsch Over a year ago

reading someone's mind, probably ... you might be able to copy/paste this answer to the new question which may be in the making

user2475404 Over a year ago

Ill erase my newly made question, you are a lifesaver, thank you sir.

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