I'm trying to get random hex value between range of hexes:
random.randint(0xfff000, 0xffffff)
I got the range limits from JSON, as a string.
{"range": "0xfff000,0xffffff"}
How can I convert these strings(after splitting) to hexadecimal values?
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Note that "values" are neither decimal, nor binary, nor yet hexidecimal. It is only the representation, e.g. strings, that have place-value at all.jpaugh– jpaugh2013-06-18 17:42:43 +00:00Commented Jun 18, 2013 at 17:42
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2 Answers
Use the built-in int() function with a base of 16:
>>> int('0xfff000', 16)
16773120
>>> int('0xfff000', 16) == 0xfff000
True
2 Comments
Blender
+1, I never knew that
int accepted strings prefixed like that.
Andrew Clark
Yeah I had to double check it, was about to write an answer that stripped the
0x off first but it is nice that it isn't necessary.You could utilise the following:
from random import randint
d = {"range": "0xfff000,0xffffff"}
print randint(*(int(i, 16) for i in d['range'].split(',')))
# 16775837
And then expand that to customise your own random integer function, eg:
from random import randint
from functools import partial
d = {"range": "0xfff000,0xffffff"}
my_random = partial(randint, *(int(i, 16) for i in d['range'].split(',')))
print [my_random() for n in range(5)]
# [16776381, 16774349, 16776922, 16773212, 16775873]
