Php regex: replacing localization string

Question

The Stackoverflow user Casimir et Hippolyte gave me this awesome function to replace strings like [[ Something ]] with localized strings being returned with $this->_() function.

$that = $this;
$view = preg_replace_callback('~\[\[\K(?>[^]]++|](?!]))*~', function ($m) use ($that) {
   return $that->__($m[0]); }, $view);

It works except that it doesn't replace the brackets. So, if I have "Yes|Ja" my I18n file, and in my view file I write [[ Yes ]] it comes up with [[ Ja ]].

I've spent a few hours trying and googling but unfortunately - nothing. Any ideas?

Casimir et Hippolyte · Accepted Answer · 2014-12-08 18:10:08Z

1

Sorry, you can replace your pattern by:

$that = $this;
$view = preg_replace_callback(
        '~\[\[((?:[^]]+|](?!]))*+)]]~', function ($m) use ($that) {
        return $that->__($m[1]); }, $view);

edited Dec 8, 2014 at 18:10

answered Jun 22, 2013 at 6:39

Casimir et Hippolyte

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Ro Yo Mi · Accepted Answer · 2013-06-22 01:20:30Z

1

This will capture the two square brackets \K\[\[(?>[^]]++|](?!]))]]*

Input Text

like [[ yes|ja ]] with

Matches

[0] => [[ yes|ja ]]
[1] => yes|ja

I"m not a python programmer, but I think you'll want to modify your script to be like this:

$that = $this;
$view = preg_replace_callback('~\K\[\[(?>[^]]++|](?!]))]]*~', function ($m) use ($that) {
   return $that->__($m[1]); }, $view);

answered Jun 22, 2013 at 1:20

Ro Yo Mi

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