PowerShell Copy-Item what I'm doing wrong?

Question

Given the dir structure:

x\Code
x\Script\Backup.ps1

Backup.ps1 contains:

$BackupDirectoy       = "..\Backup"
$CodeDirectory        = "..\Code"

function BackupCurrentVersion()
{
  New-Item $BackupDirectoy -type directory -force
  Copy-Item $CodeDirectory -destination $BackupDirectory -recurse
}

BackupCurrentVersion

I'm doing something wrong because Code gets copied in x\Script\Code instead of x\Backup\Code

What is the problem?

Haha. Just found the problem. It's a typo "BackupDirectoy" - forgot an 'r'. Damn. I've spent 2 hours on this problem — Victor Hurdugaci
– Victor Hurdugaci, Commented Nov 12, 2009 at 20:33
You can avoid these kinds of problems by using Set-StrictMode cmdlet at the start of your script. It will not let you use any variables you have not declared (it would have caught this error). — x0n
– x0n, Commented Nov 12, 2009 at 23:16

Keith Hill · Accepted Answer · 2009-11-12 20:21:19Z

5

$BackupDirectoy       = "..\Backup"
$CodeDirectory        = "..\Code"

These paths are going to be relative to the current dir your prompt is sitting in when you run the script. I suspect you don't want that but want to run relative to where the script is located. Try this if this is the case:

$ScriptDir      = Split-Path $MyInvocation.MyCommand.Path -Parent
$BackupDirectoy = "$ScriptDir\..\Backup"
$CodeDirectory  = "$ScriptDir\..\Code"

answered Nov 12, 2009 at 20:21

Keith Hill

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1 Comment

Victor Hurdugaci Over a year ago

Actually I want the paths to be relative to script location. The current dir in PowerShell is set to x\Script

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