Find and Replace using Regular Expression

Question

Well the answer should be very simple.But i am new to the regular expression.

What i want to do is just find and replace :

Eg: iti$%#sa12c@#ombina#$tion.43of//.45simp5./l7e5andsp75e$%cial23$#of%charecters

In the above sentence replace the words "of" with "in"

I tried this but didn't get the result, please help me out.

string="iti$%#sa12c@#ombina#$tion.43of//.45simp5./l7e5andsp75e$%cial23$#of%charecters";
var string2=string.replace("/(\w*\W*)of(\w*\W*)/g","$1in$2");
console.warn(string2);

Denys Séguret · Accepted Answer · 2013-06-22 11:49:21Z

4

Fix the regex literal (no quotes) and use word boundaries (\b, no need to use $1 and $2) :

var string2 = string.replace(/\bof\b/g, "in");

answered Jun 22, 2013 at 11:49

Denys Séguret

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Comments

Niccolò Campolungo · Accepted Answer · 2013-06-22 11:51:11Z

2

Why not a simple var replaced = yourString.replace(/of/g, 'in');?

answered Jun 22, 2013 at 11:51

Niccolò Campolungo

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1 Comment

Denys Séguret Over a year ago

This doesn't replace "words", as this would also match "of" when not a complete word.

Xotic750 · Accepted Answer · 2013-06-22 12:21:27Z

1

Globally replace without using a regex.

function replaceMulti(myword, word, replacement) {
    return myword.split(word).join(replacement);
}

var inputString = 'iti$%#sa12c@#ombina#$tion.43of//.45simp5./l7e5andsp75e$%cial23$#of%charecters';

var outputString = replaceMulti(inputString, 'of', 'in');

edited Jun 22, 2013 at 12:21

Xotic750

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answered Jun 22, 2013 at 11:49

Ganesh Rengarajan

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2 Comments

Alp Over a year ago

Also, this is not Haskell.

Xotic750 Over a year ago

This doesn't replace "words", as this would also match "of" when not a complete word.

Jonathan · Accepted Answer · 2013-06-22 11:50:26Z

0

Like this?

str.replace("of","in");

answered Jun 22, 2013 at 11:50

Jonathan

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2 Comments

Niccolò Campolungo Over a year ago

This will replace only one occurence, not all

Xotic750 Over a year ago

This also doesn't replace "words", as this would also match "of" when not a complete word.

Khanh TO · Accepted Answer · 2013-06-22 11:50:27Z

0

Regular expressions are literals or objects in JavaScript, not strings.

So:

/(\w*\W*)of(\w*\W*)/g

or:

new Regexp("(\\w*\\W*)of(\\w*\\W*)","g");

edited Jun 22, 2013 at 11:50

Khanh TO

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answered Jun 22, 2013 at 11:49

Tim

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