How do I post a row of data to another script? [duplicate]

Question

<?php 
    $pvp=mysql_query("SELECT * FROM characters ORDER BY level DESC");
echo "<table><tr><th>Character</th><th>Level</th><th>Tribe</th></tr>";
while ($row = mysql_fetch_array($pvp)) {
    echo "<tr><td>".($row['charname'])."</td><td>".($row['level'])."</td><td>".($row['tribe'])."</td><td><form action='/scripts/pvp.php' method='post'><input type='submit' name='pvp' value='Battle!'></form></td></tr>";
}
echo "</table>";
?>

In this script, I loop through an array and display all data stored in a variable ($pvp). I would like to add an input button at the end of each row that allows me to post that specific row to another page to use in another script. How would I do this?

You could populate form inputs with PHP just like you are populating your table: <input type="text" name="charname" value="<?=$row['charname']?>" /> — showdev
– showdev, Commented Jun 25, 2013 at 18:31

drull · Accepted Answer · 2013-06-25 18:59:26Z

0

Inside while() loop:

echo "<tr><td>".($row['charname'])."</td>";
echo "<td>".($row['level'])."</td><td>".($row['tribe'])."</td>";
echo "<td><form action='/scripts/pvp.php' method='post'>";
echo "<input type=hidden name='tribe' value='".$row['tribe']."'>";
echo "<input type=hidden name='charname' value='".$row['charname']."'>";
echo "<input type=hidden name='level' value='".$row['level']."'><input type='submit' name='pvp' value='Battle!'></form></td></tr>";

edited Jun 25, 2013 at 18:59

answered Jun 25, 2013 at 18:35

drull

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3 Comments

Mikifer Blair Over a year ago

Adding the hidden inputs into my loop breaks my current page.

Mikifer Blair Over a year ago

Previously, my script - sans form - would display a table that had 3 rows of information, plus the headers. When I add that to the script, the page displays blank.

drull Over a year ago

Oh, yeah, forgot to remove extra "(". Try now.

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