std::unique_ptr with derived class

Question

I have a question about the c++11 pointers. Specifically, how do you turn a unique pointer for the base class into the derived class?

class Base
{
public:
   int foo;
}

class Derived : public Base
{
public:
   int bar;
}

...

std::unique_ptr<Base> basePointer(new Derived);
// now, how do I access the bar member?

it should be possible, but I can't figure out how. Every time I try using the

basePointer.get()

I end up with the executable crashing.

Thanks in advance, any advice would be appreciated.

Could you show a complete (but minimal) example of the code that causes your process to crash? basePointer.get() alone certainly isn't a problem. — jogojapan
– jogojapan, Commented Jul 2, 2013 at 5:26
@jogojapan I fixed my problem. I was doing some really weird casting with at least 5 sets of parenthesis. I'm pretty sure it was just something stupid, but I already changed it and don't remember what I did. Captain Obvlious' answer worked for me though. Thanks for all your help! — Lukas Schmit
– Lukas Schmit, Commented Jul 2, 2013 at 5:32

Captain Obvlious · Accepted Answer · 2013-07-02 05:22:33Z

60

If they are polymorphic types and you only need a pointer to the derived type use dynamic_cast:

Derived *derivedPointer = dynamic_cast<Derived*>(basePointer.get());

If they are not polymorphic types only need a pointer to the derived type use static_cast and hope for the best:

Derived *derivedPointer = static_cast<Derived*>(basePointer.get());

If you need to convert a unique_ptr containing a polymorphic type:

Derived *tmp = dynamic_cast<Derived*>(basePointer.get());
std::unique_ptr<Derived> derivedPointer;
if(tmp != nullptr)
{
    basePointer.release();
    derivedPointer.reset(tmp);
}

If you need to convert unique_ptr containing a non-polymorphic type:

std::unique_ptr<Derived>
    derivedPointer(static_cast<Derived*>(basePointer.release()));

answered Jul 2, 2013 at 5:22

Captain Obvlious

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8 Comments

Marc Over a year ago

Are you sure there's no memory leak when you do basePointer.release()?

meneldal Over a year ago

@Marc The reason it is safe is because both release() and reset() are noexcept, so unless you are doing something very bad outside this function, the raw pointer will always end up in the derived pointer and will be correctly destroyed.

Masadow Over a year ago

It might be obvious for some but please note that you are stealing the resource from the basePointer which is not always what you want in your unique_ptr conversion

Daniel McLaury Over a year ago

@Masadow: If it's not what you want, then you don't want a unique pointer.

Johan Boulé Over a year ago

Problem with the answer. Yes, static_cast does also support polymorphic types. You should only use dynamic_cast when you're unsure whether the cast will work or fail (and in this case, test whether it returned null as you did).

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