PHP Parse Date From String

Question

I received a date string from API respond like this

"2013-07-09T04:58:23.075Z"

How can I parse that string, say to change format to

2013-07-09 [04:58:23]

The time indeed is not based on my local time, I think the .075Z should change something about the time.

Thanks in advance for your help.

Yogesh Suthar · Accepted Answer · 2013-07-09 06:01:07Z

10

You can do that using the DateTime object.

$Date = new DateTime('2013-07-09T04:58:23.075Z'); //create dateTime object
$Date->setTimezone(new DateTimeZone('Europe/Amsterdam')); //set the timezone

echo $Date->format('d/m/Y H:i');

edited Jul 9, 2013 at 6:01

Yogesh Suthar

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answered Jul 9, 2013 at 5:56

Benz

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3 Comments

Ardeus Over a year ago

It seems it works. it knows because of 75Z mean 75 minutes from UTC or GMT sort of time?

vascowhite Over a year ago

@Ardeus The .075 is 75 microseconds and the Z (pronounced Zulu) indicates the time is in UTC.

rew Over a year ago

.075 is miliseconds (not microseconds).

Lucas Lim · Accepted Answer · 2013-07-09 06:01:26Z

2

try this

$date = '2013-07-09T04:58:23.075Z';
$seconds = strtotime($date);

echo date('Y-m-d [H:i:s]', $seconds);

Hope it helps!

answered Jul 9, 2013 at 6:01

Lucas Lim

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1 Comment

Benz Over a year ago

And what about the timezone?

vascowhite · Accepted Answer · 2013-07-09 11:45:09Z

1

$time = "2013-07-09T04:58:23.075Z";
$exp = explode('T',$time);
echo $exp[0] .' [' .substr($exp[1], 0, -5) . ']';

I'm using it like this.

edited Jul 9, 2013 at 11:45

vascowhite

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answered Jul 9, 2013 at 6:03

Alfath Dirk

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Comments

Shaw Donayre · Accepted Answer · 2016-07-21 04:25:48Z

-1

@Benz

simply add below:

date_default_timezone_set('Australia/Brisbane');

echo date('d/m/Y H:i', strtotime('2013-07-09T04:58:23.075Z'));

were done! Hope this help.

edited Jul 21, 2016 at 4:25

answered Jul 21, 2016 at 4:11

Shaw Donayre

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