MIPS Converting integer to float

Question

I'm really new in MIPS assembly and I am wondering can I do something like:

enter image description here Not just three characters number, any length of X and Y

Please help If you know the algorithm or where can I find the code or algorithm

(Sorry I thought image might describe better and faster)

Thank you ...

Yes, you can do that. You're going to have to jump through some hoops. Did you try anything? — Carl Norum
– Carl Norum, Commented Jul 10, 2013 at 5:03
Yes. actually I'm trying since Friday but still nothing, That's why I asked my question here. — Node.JS
– Node.JS, Commented Jul 10, 2013 at 5:04
@Hooman: What Carl Norum asked, is to post some come you tried that an be commented to help you to make it work. SO is dedicated to coding problems, if you have some code even broken, post it. SO is not a place to ask others to write your code. — Seki
– Seki, Commented Jul 10, 2013 at 7:59

Konrad Lindenbach · Accepted Answer · 2013-07-10 12:20:56Z

1

Consider the following pseudo-code:

int x = input
int y = input

while y > 1:
    y = y / 10

return x + y

Of course you will have to be cognizant of the normal floating point precision sticking points, i.e. that this can only at best get you as close as possible to XXX.YYY given the representation.

answered Jul 10, 2013 at 12:20

Konrad Lindenbach

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3 Comments

Drew McGowen Over a year ago

Perhaps OP should clarify on how the length of Y is specified, but this does not work if I want, for example, X=34 and Y=2 to result in 34.02.

Konrad Lindenbach Over a year ago

@DrewMcGowen That's a good point. I didn't consider the case of leading zeros in Y because Y is an integer. If that is required then a slightly different approach must be taken.

Drew McGowen Over a year ago

If you have the digit length, you can just replace the while loop with a for loop.

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