I have a string which looks like this when I print it:
RT @HHRoadGuy: It's that time again! Time to tune in for the latest #fortheloveofmusic episode. Catch it now on @CMT!
http://t.co/VatlhGq9…
I tried to get rid of the linespacing with:
tweet = tweet.rstrip('\r\n')
But it does not work. Probably as the linespacing is inbetween. Also the replace function could not help. What can I do here?
Are you sure that the line delimeters are indeed '\r\n' and not just '\n'?
Because replace() should work just fine:
>>> s = 'hello\r\n\r\nhi'
>>> print(s)
hello
hi
>>> s2 = s.replace('\r\n\r\n', '\r\n')
>>> print(s2)
hello
hi
Indeed, the rstrip() will not work, since that function only strips on the right (end) of the string.
There are many line break characters:
\n \n\r \r depending on the text input.
Look http://en.wikipedia.org/wiki/Newline, depending on your input text and replace that character
The following should work in most cases to get rid of all line breaks, regardless of how they're represented:
lines = tweet.splitlines()
tweet = " ".join(lines)
Or, to avoid double spacing (and adopting P.M.'s concept):
tweet = " ".join([line for line in lines if len(line)])
If you wanted to only get rid of blank lines but preserve line breaks:
tweet = "\n".join([line for line in lines if len(line)])
tweet = tweet.replace('\n','')
Is the answer. I just had a tiny error in my code and after trying all these different methods and things I got blind. Sorry!
Try this :
>>> '\n'.join([line for line in your_text.splitlines() if line.strip()])
See http://docs.python.org/2/library/stdtypes.html#str.splitlines for more informations on how it handles line breaks.
