Replace a ruby regular expression pattern with a variation of that pattern, within a string

Question

I have this string: "@OKFN @417_tw The _European Commission; && _European Governments; are consulting on Open Research Data; read our response: http://blog.okfn.org/2013/07/16/ec-consultation-on-open-research-data" and i want to replace all couples of words preceded by "_" and ended with ";" by the same words but without those characters.

Here's how i did it, but i dont think its very neat. Would there be a better way to do it?

subj="@OKFN @417_tw The _European Commission; && _European Governments; are consulting on Open Research Data; read our response: http://blog.okfn.org/2013/07/16/ec-consultation-on-open-research-data"

tags=subj.scan(/_[a-zA-Z0-9]+\s*[a-zA-Z0-9]+;/)

tags.each do |t|
    t.gsub!(/_|;/,"")
    subj.sub!("_"+t+";",t)

end

puts subj

but not in all ocurrencies means ? give us a sample short string and the expected output from that string. Myself at-least not getting the point of yours. — Arup Rakshit
– Arup Rakshit, Commented Jul 16, 2013 at 15:11
not in 417_tw for instance, just when its 2 words, the first one preceded by "_" and the last one ended in ";" — fartagaintuxedo
– fartagaintuxedo, Commented Jul 16, 2013 at 15:14

sawa · Accepted Answer · 2013-07-16 15:13:17Z

1

To do what you describe:

subj.gsub(/_([^_;]*);/, '\1')

If you just want to delete "_" and ";", then this:

subj.tr("_;", "")

edited Jul 16, 2013 at 15:13

answered Jul 16, 2013 at 15:08

sawa

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1 Comment

fartagaintuxedo Over a year ago

this is removing "_" from the twitter user @417_tw

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